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Komok [63]
3 years ago
14

Determine the range of the function f(x)=x^2-2/2 when the domain is {0, 2}. HELP

Mathematics
1 answer:
lawyer [7]3 years ago
7 0

The range of function is { -1, 1 }

<em><u>Solution:</u></em>

Given that, the function is:

f(x) = \frac{x^2-2}{2}

Domain is {0, 2 }

We have to find the range of function

The domain refers to the set of possible input values

The range is the set of possible output values

Here domain is x = 0 and x = 2

<em><u>Substitute x = 0 in given function</u></em>

f(0) = \frac{0-2}{2}\\\\f(0) = \frac{-2}{2}\\\\f(0) = -1

<em><u>Substitute x = 2 in given function</u></em>

f(2) = \frac{2^2-2}{2}\\\\f(2) = \frac{4-2}{2}\\\\f(2) = \frac{2}{2} = 1

Thus the range of function is { -1, 1 }

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