Water is able to travel up stems to leaves in a plant. this is an example of ____

1.00 liter solution contains 0.31 M acetic acid and 0.40 M sodium acetate. If 0.100 moles of calcium hydroxide are added to this

kodGreya [7K]

Answer:

The answer is the explanation.

Explanation:

The acetic acid, CH3COOH, reacts with calcium hydroxide, Ca(OH)2, producing acetate ion, CH3COO- and water as follows:

2CH3COOH + Ca(OH)2 → 2CH3COO- + 2H2O + Ca²⁺

That means the moles of acetic acid decrease whereas the moles of acetate ion are increased. The ratio of [CH3COOH] / [CH3COO-] is different.

As a base is added, the concentration of H3O+ decreases increasing the pH.

That means:

TRUE A. The number of moles of CH3COOH will decrease.

FALSE B. The number of moles of CH3COO- will decrease.

TRUE C. The equilibrium concentration of H3O will decrease.

FALSE D. The pH will decrease.

FALSE E. The ratio of [CH3COOH] / [CH3COO-] will remain the same.

5 0

3 years ago

Which ionic compound would you predict to have a higher boiling point: NaBr or

nasty-shy [4]

Answer:

The boiling point of NaBr is higher than that of Na2S

Explanation:

Bromine has higher electronegativity as compared to the sulphur. The ionic strength of the bond formed with Sodium is higher in the NaBr compound. The higher the ionic bond strength the higher will be the boiling point

Also the size of bromine is large as compared to that of sulphur. Large molecules consists of more electron and hence they create der Waals attractive forces due to which the boiling point of compound increases.

Hence, the boiling point of NaBr is higher than that of Na2S

8 0

3 years ago

Which science tool colud be used to reflect light

kvasek [131]

A mirror reflects light

5 0

3 years ago

The amount of I−3(aq) in a solution can be determined by titration with a solution containing a known concentration of S2O2−3(aq

Pavlova-9 [17]

Answer : The molarity of $I_3^-$ in the solution is, 0.128 M