The sum of the first 75 terms of the arithmetic sequence that has 10th term as 16 and the 35th term as 66 is 5400.
<h3>How to find the sum of terms using Arithmetic sequence formula</h3>
aₙ = a + (n - 1)d
where
Therefore, let's find a and d
a₁₀ = a + (10 - 1)d
a₃₅ = a + (35 - 1)d
Hence,
16 = a + 9d
66 = a + 34d
25d = 50
d = 50 / 25
d = 2
16 - 9(2) = a
a = 16 - 18
a = -2
Therefore, let's find the sum of 75 terms of the arithmetic sequence
Sₙ = n / 2 (2a + (n - 1)d)
S₇₅ = 75 / 2 (2(-2) + (75 - 1)2)
S₇₅ = 37.5 (-4 + 148)
S₇₅ = 37.5(144)
S₇₅ = 5400
learn more on arithmetic sequence here: brainly.com/question/1687271
Answer:
4+(3x2)-4/2
Step-by-step explanation:
pemdas
Answer:
.
Step-by-step explanation:
3x - y = 17 .......A
10 × [x/5 + y/2] = 10 × 0
2x + 5y = 0 .......B
......A× 5 both 2 sides of equation
15x - 5y = 85 .....C
......B + ........C
2x + 15x = 0 + 85
17x = 85
x = 85/17
x = 5
put x value in ........A or .......B or ......C
you will receive y = -2
Answer:
76
Step-by-step explanation:
456 divided by 6 equals 76. Hope that helps.
