The mean is -4 cause u have to add ale the numbers togeter
Step-by-step explanation:
let us give all the quantities in the problem variable names.
x= amount in utility stock
y = amount in electronics stock
c = amount in bond
“The total amount of $200,000 need not be fully invested at any one time.”
becomes
x + y + c ≤ 200, 000,
Also
“The amount invested in the stocks cannot be more than half the total amount invested”
a + b ≤1/2 (total amount invested),
=1/2(x + y + c).
(x+y-c)/2≤0
“The amount invested in the utility stock cannot exceed $40,000”
a ≤ 40, 000
“The amount invested in the bond must be at least $70,000”
c ≥ 70, 000
Putting this all together, our linear optimization problem is:
Maximize z = 1.09x + 1.04y + 1.05c
subject to
x+ y+ c ≤ 200, 000
x/2 +y/2 -c/2 ≤ 0
≤ 40, 000,
c ≥ 70, 000
a ≥ 0, b ≥ 0, c ≥ 0.
Answer: -16
Step-by-step explanation:
49 would be the result of -7 squared. Due to the fact it is negative, it would cancel out to be positive.
For the numerator, 49-1 is equivalent to 48.
48/x+4
-7+4 = -3
48/-3
= -16
Answer:
Please check the explanation and attached graph.
Step-by-step explanation:
Given the parent function
y = |x|
In order to translate the absolute function y = |x| vertically, we can use the function
g(x) = f(x) + h
when h > 0, the graph of g(x) translated h units up.
Given that the image function
y=|x|+4
It is clear that h = 4. Since 4 > 0, thus the graph y=|x|+4 translated '4' units up.
The graph of both parent and translated function is attache below.
In the graph,
The blue line represents the parent function y=|x|.
The red line represents the image function y=|x| + 4.
It is clear from the graph that the y=|x| + 4 translated '4' units up.
Please check the attached graph.
The answer would be 45. Thank you very much and good luck on there!
