Twice a number increased by 5= 2x+5
5 decreased by twice a number= 5-2x
twice the difference of a number and 5= 2(x-5)
Twice the sum of a number and 5= 2(x+5)
Five subtracted from twice a number= 2x-5
Twice a number, less 5= 2x-5
Answer: Y is less than or equal to 65 and X + y= less than or equal to 95
Answer:
You will save 6,500
Explanation:
There are 52 weeks in one year multiply 52 times 125
The extraneous solution of startroot 4 x 41 endroot = x 5 will be A. -8.
<h3>What is an extraneous solution?</h3>
It should be noted that an extraneous solution simply means a root of a transformed equation which isn't part of the original equation.
✓4x + 41 = x + 5
Square both sides
4x + 41 = x² + 10x + 25
x² + 6x - 16
x(x + 8) - 2(x + 8) = 0
x + 8 = 0
x= 0 + 8 = 8
Learn more about extraneous solution on:
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