180-129= 51
angle 4 is equal to angle 12 so missing angle 12= 51°
(1,2)
The solution is where the lines intersect so you can see they intersect at (1,2)
The given circles are given in standard form:
(x - xc)² + (y - yc)² = r²
The second quadrant is the one that has negative x coordinates and positive y coordinates.
This said, let's see all your options:
A) (x - 5)² + (y - 6)² = 25
xc = -(-5) = +5
yc = -(-6) = +6
C (5 , 6) is in the first quadrant.
B) (x + 1)² + (y - 7)² = 16
xc = -(+1) = -1
yc = -(-7) = +7
C (-1 , 7) is in the second quadrant.
C) (x - 4)² + (y + 3)² = 32
xc = -(-4) = +4
yc = -(+3) = -3
C (4, -3) is in the fourth quadrant.
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D) (x + 2)² + (y - 5)²= 9</span>
xc = -(+2) = -2
yc = -(-5) = +5
C (-2 , +5) is in the second quadrant.
Therefore, the correct answers are B and D.
Hey There!
your win/lose ratio is 5/6 and you have 10 on your first one 5×2=10 so 6×2=12
the other one you have 18 so 6×3=18 so, 5×3=15 thus these being your answers.
Hope This Helps!!!
