All categories

3 years ago

Last year, Jason's average in math was a 72. This year, his average is a 90. What is the percent increase in Jason's grade?

Mathematics

1 answer:

slamgirl [31]3 years ago

7 0

Answer:

20% increase

Step-by-step explanation:

All you have to do is divide 72 by 90n and it will give you .8, move the decimal two places to the right to give you 80 and subtract 80 from 100 to get 20

You might be interested in

PLS HELP! DUE IN 30 MINUTES!

gayaneshka [121]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Janelle has 5 hours to spend training for an upcoming race. She completes her training by running full speed the distance of the

VikaD [51]

Answer:

The distance cover by him walking back is 11.25 miles

Step-by-step explanation:

Given as :

Time for Janelle to spend on training = 5 hours

The running speed of Janelle = 9 mph

The walking back with 3 mph

Let The distance for running and walking is same i.e D miles

SO, Time = $\frac{Distance}{Speed}$

∴ 5 = $\frac{D}{9}$ + $\frac{D}{3}$

Or, 5 × 9 = D + 3 D

Or, 45 = 4 D

∴ D = $\frac{45}{4}$ = 11.25 miles

Hence The distance cover by him walking back is 11.25 miles Answer

6 0

3 years ago

The Ace Novelty company produces two souvenirs: Type A and Type B. The number of Type A souvenirs, x, and the number of Type B s

Molodets [167]

Answer:

500 type A; 3500 type B

Step-by-step explanation:

The method of Lagrange multipliers can solve this quickly. For objective function f(x, y) and constraint function g(x, y)=0 we can set the partial derivatives of the Lagrangian to zero to find the values of the variables at the extreme of interest.

These functions are ...

$f(x,y)=4x+2y\\g(x,y)=2x^2+y-4$

The Lagrangian is ...

$\mathcal{L}(x,y,\lambda)=f(x,y)+\lambda g(x,y)\\\\\text{and the partial derivatives are ...}\\\\\dfrac{\partial \mathcal{L}}{\partial x}=\dfrac{\partial f}{\partial x}+\lambda\dfrac{\partial g}{\partial x}=4+\lambda (4x)=0\ \implies\ x=\dfrac{-1}{\lambda}\\\\\dfrac{\partial \mathcal{L}}{\partial y}=\dfrac{\partial f}{\partial y}+\lambda\dfrac{\partial g}{\partial y}=2+\lambda (1)=0\ \implies\ \lambda=-2$

$\dfrac{\partial\mathcal{L}}{\partial\lambda}=\dfrac{\partial f}{\partial\lambda}+\lambda\dfrac{\partial g}{\partial\lambda}=0+2x^2+y-4=0\ \implies\ y=4-2x^2\\\\\text{We know $\lambda$, so we can find x and y:}\\\\x=\dfrac{-1}{-2}=0.5\\\\y=4-2\cdot 0.5^2=3.5$

Since x and y are in thousands, maximum profit is to be had when the company produces ...

500 Type A souvenirs, and 3500 Type B souvenirs

3 0

3 years ago

Kevin is making us a call model of the Statue of Liberty which is 306 feet tall if the model is 1/10 of the actual statue of Lib

anastassius [24]

Model of Statue of Liberty is 30.6 feet tall.

<u>Step-by-step explanation:</u>

Given the Statue of Liberty is 306 feet tall. If the model is 1/10 the actual size of the Statue of Liberty.

Actual size of the statue = 306

Model is $\frac{1}{10}$ of the actual size of the Statue of Liberty

Height of model = $\frac{1}{10}$ of the actual size

= $\frac{1}{10}$ * 306

= 30.6 feet

Model of Statue of Liberty is 30.6 feet tall.

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=y%20%3D%206x%20%2B%2015" id="TexFormula1" title="y = 6x + 15" alt="y = 6x + 15" align="absmidd

gizmo_the_mogwai [7]

1) remove the variable (y=6+15)
2)solve (y=6+15= 21)
3) put it together (y=21)
4) add the variable (y=21x)

5 0

3 years ago