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Tema [17]
3 years ago
9

A=student is female

Mathematics
1 answer:
Aleks04 [339]3 years ago
4 0
<span>For "The probability a business major is female" - you're looking for the probability of being female. That the person is a business major is already given. So, P(A|B)

</span>For "The probability a female student is majoring in business" - you're looking for the probability of being majoring in business. That the person is a female is already given. So, P(B|A)
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What is the measure of angle C, to the nearest degree? (Image Attached)
worty [1.4K]
Answer: (B) - 43°
Explanation: Using the sine rule, we can say that sinA/BC = sinC/AB
sin(61)/45 = sin(C)/35
sin(C) = 35sin(61)/45

sin(C) ≈ 0.680259772....
C = arcsin(0.680259772...)

C = 42.8639459...
C ≈ 43°
4 0
3 years ago
Read 2 more answers
Tanya runs a catering business. Based on her records, her weekly profit can be approximated by the function, where x is the numb
uranmaximum [27]

answer is in image attached

7 0
3 years ago
Simplify -4(-8x-8) in distributive property
frosja888 [35]

Answer:

32x+32

Step-by-step explanation:

In the distributive property, you have to multiply the thing outside the parenthesis to each term in the parenthesis. -4*-8x=32x and -4*-8=32, so the answer would be 32x+32

4 0
3 years ago
Find each product.<br><br> 1. (5a3b)(2ab)<br><br> 2.5y(-y2+7y-2)<br><br> PLEASE HELP!!?!
maks197457 [2]

Answer:

<h2>1).</h2>

(5a3b)(2ab)

Expand

That's

15ab( 2ab )

we have the answer as

<h3>30a²b²</h3>

<h2>2).</h2>

5y(-y² + 7y - 2)

Expand

That's

<h3>- 5y³ + 35y² - 10y</h3>

Hope this helps you

5 0
3 years ago
Let Q(x, y) be the predicate "If x &lt; y then x2 &lt; y2," with domain for both x and y being R, the set of all real numbers.
Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is Q(x,y) is predicate that x then x^{2}. where x,y are rational numbers.

a)

when x=-2, y=1

Here -2 that is x  satisfied. Then

(-2)^{2}

4 this is wrong. since 4>1

That is x^{2}>y^{2} Thus Q(x,y) =Q(-2,1)is false.

b)

Assume Q(x,y)=Q(-5,2).

That is x=-5, y=2

Here -5 that is x this condition is satisfied.

Then

(-5)^{2}

25 this is not true. since 25>4.

This is similar to the truth value of part (a).

Since in both x satisfied and x^{2} >y^{2} for both the points.

c)

if Q(x,y)=Q(3,8) that is x=3 and y=8

Here 3 this satisfies the condition x.

Then 3^{2}

9 This also satisfies the condition x^{2}.

Hence Q(3,8) exists and it is true.

d)

Assume Q(x,y)=Q(9,10)

Here 9 satisfies the condition x

Then 9^{2}

81 satisfies the condition x^{2}.

Thus, Q(9,10) point exists and it is true. This satisfies the same values as in part (c)

6 0
3 years ago
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