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3 years ago

How many rational numbers are between -2 and 5?

Mathematics

1 answer:

Butoxors [25]3 years ago

4 0

The answer is 7 because 2 to 5 is 3 and -2 to 5 I 7

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(Segment Proofs)

Anni [7]

Answer:

It's proved below

Step-by-step explanation:

We are given;

- K is the midpoint of JL

- M is the midpoint of LN

By definition of mid points, we can say that;

JK = KL and LM = MN

Now, we are given that JK = MN.

Thus, by substitution, we can deduce that; KL = LM

Thus is because JK can be replaced with KL and MN can be replaced with LM.

Thus, it is proved that KL = LM

4 0

3 years ago

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$b=0,b-4=0$

$b=0,b=4$

Therefore, the solutions are:

$b=0,\:b=4$

4 0

3 years ago

Read 2 more answers

Please help anyone.

Burka [1]

Answer:

- $\frac{27}{7}$

Step-by-step explanation:

Given

f(x) = $\frac{3}{x+2}$ - $\sqrt{x-3}$

Evaluate f(19) by substituting x = 19 into f(x)

f(19) = $\frac{3}{19+2}$ - $\sqrt{19-3}$

= $\frac{3}{21}$ - $\sqrt{16}$

= $\frac{1}{7}$ - 4

= $\frac{1}{7}$ - $\frac{28}{7}$ = - $\frac{27}{7}$

7 0

4 years ago

F(x)=4x+4;{-2,-1,0,1,2}

GrogVix [38]

Answer:

i need more info

Step-by-step explanation:

please comment on this to tell me all of said details

3 0

3 years ago

Read 2 more answers

Why do the probability of an event and the probability of its complement add up to 1

Ad libitum [116K]

<span>the probability of an event and the probability of its complement add up to 1 because the total events are the even it self and its compliment, so its probability equal to 1 because these are all the possible events that will occur. for example a coin toss, an event head will happen 0.5, and its complement is tails which will also happens 0.5</span>

5 0

3 years ago