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3 years ago

What is the coefficient in the expression 15y + 5

Mathematics

2 answers:

dalvyx [7]3 years ago

8 0

Answer:

Step-by-step explanation:

If helpful, please give 5 star, thanks, and brainliest!

Nikitich [7]3 years ago

6 0

-20 because 15 it’s ro moved

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The admission fee at a small fair is $1.50 for children and $4.00 for adults. John spent $12.00 for admission. Write an equation

g100num [7]

So what you are trying to find is the certain amount of children tickets and adult tickets. the final amount is a total of $12. This means that a unknown number of children tickets (c) times 1.50 (price of each ticket for children) plus the unknown number of adult tickets (a) times 4.00 (price of each ticket for adults) equals a final cost of $12.00.

Equation: 1.50c+4.00a= 12.00

4 0

3 years ago

A rectangle has a length 6 more than it's width if the width is decreased by 2 and the length decreased by 4 the resulting has a

Rashid [163]

Answer:

Length of original rectangle: 11 units.

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

$\text{Perimeter of new rectangle}=20$

Step-by-step explanation:

Let x represent width of the original rectangle.

We have been given that a rectangle has a length 6 more than it's width. S the length of the original rectangle would be $x+6$ .

We have been given that when the width is decreased by 2 and the length decreased by 4 the resulting has an area of 21 square units.

The width of new rectangle would be $x-2$ .

The length of new rectangle would be $x+6-4=x+2$ .

The area of new rectangle would be $(x+2)(x-2)$ .

Now we will equate area of new rectangle with 21 and solve for x as:

$(x+2)(x-2)=21$

Applying difference of squares, we will get:

$x^2-2^2=21$

$x^2-4=21$

$x^2-4+4=21+4$

$x^2=25$

Since width cannot be negative, so we will take positive square root of both sides.

$\sqrt{x^2}=\sqrt{25}$

$x=5$

Therefore, the width of original rectangle is 5 units.

Length of the original rectangle would be $x+6\Rightarrow x+5=11$ .

Therefore, the length of original rectangle is 11 units.

$\text{Area of original rectangle}=5\times 11$

$\text{Area of original rectangle}=55$

Therefore, area of the original rectangle is 55 square units.

Now we will find ratio of the original rectangle area to the new rectangle area as:

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

We know that perimeter of rectangle is two times the sum of length and width.

$\text{Perimeter of new rectangle}=2((x+2)+(x-2))$

$\text{Perimeter of new rectangle}=2((5+2)+(5-2))$

$\text{Perimeter of new rectangle}=2(7+3)$

$\text{Perimeter of new rectangle}=2(10)$

$\text{Perimeter of new rectangle}=20$

Therefore, the perimeter of the new rectangle is 20 units.

7 0

4 years ago

Fill in missing numbers in chart. state the rule

tester [92]

On the left side, the blank is 22, but I am clueless on the right side

3 0

3 years ago

Read 2 more answers

Can anyone help I’ll mark brainliest:)

Dima020 [189]

Answer:

Problem 10:

Input X: -2, -1, 0, 1, 2

Output Y: -2, 1, 2, 1, -2

Nonlinear, exponential because there's an exponent. Plug the X values in place of X and solve solution to get Y values. Then graph

Problem 11: Linear because there's no exponent

8 0

3 years ago

5x-3.5=12.5 what is x?

Vadim26 [7]

Answer:

x=3.2

Step-by-step explanation:

12.5+3.5=16

16÷5= 3.2

6 0

3 years ago