I see two lines, a and b, one superimposed on top the other. In such a case, there is an infinite number of solutions.
Answer:
Step-by-step explanation:
The general equation of a circle can be expressed as (x-a)²+(y-b)² = r² where (a,b) is the centre of the circle and r is the radius.
To show that the equation x² + y² +6y + 2 = 0 represents a circle, we need to write it in the format above using the completing the square method.
Given x² + (y² +6y) + 2 = 0
First we need to complete the square of the square in parenthesis by adding the square of half of the coefficient of y i.e
to the equation and adding the constant to the other side of the equation as well.
x² + (y² +6y) + 2 = 0

<em>Hence the equation represents a circle with centre C at (0, -3) and radius of √7</em>


<h2>Step-by-step explanation :</h2>
Total shared part:
1/4 + 1/8
Taking LCM and adding:
2/8+1/8
Adding gives:
3/8
Here is your first answer:
First find whats common which is 6:
-4×2=-8
3×2=6
-3×3=-9
2×3=6
Subtract -9 and -8
But use KCC which makes the equation...
-9+8=-1
-1/6
Here is your second answer:
First use KCC to Chang the equation into...
-3.9
-8.9
Then add:
9+9=18
=-1.28
Here is your third answer:
First change the equation (KCC):
2.9
9.4
9+4=13
3.9=12
=1.23
There are your answers: