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4 years ago

6)

Mathematics

1 answer:

egoroff_w [7]4 years ago

5 0

i would pick D as the answer.

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For the triangle shown below, complete the following table.

dem82 [27]

Answer:

Step-by-step explanation:

In the given triangle

With reference angle A

perpendicular (P) = 3

hypotenuse (h) = 5

So sin A = p/h = 3/5

and

With reference angle C

perpendicular (p)= 4

hypotenuse (h) = 5

Sin C = p/h = 4/5

hope it helps :)

3 0

3 years ago

Graph the equation of the line parallel to 2x−y=6 and passing through (-3, 1). Show work.

alexandr402 [8]

Answer:

It's a graph, see the image.

Step-by-step explanation:

Use the equation to find the slope. Use the slope and the point to graph the line.

7 0

3 years ago

Just need help with 2 and 4 :)

vesna_86 [32]

2.)

0 = 6x + 3y +9
-3y = 6x + 3y - 3y +9

$\frac{ - 3y}{ - 3} = \frac{6x + 9}{ - 3} \\ \\ y = - 2x - 3$
By isolating y we now have the equation in slope intercept form:
$y = mx + b$

Where m = slope and b = y- intercept. Therefore, the slope is -2 and the y - intercept is -3.

4.)

Similarly, #4 is already in slope intercept form so we can solve it by inspection. So for #4 the slope is -1 and the y - intercept is 2.

7 0

3 years ago

Factor. Z^2- 3z – 18

Alecsey [184]

Answer:

(z-6)(z+3)

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

Please help me with the below question.

tresset_1 [31]

We have the following three conclusions about the piecewise function evaluated at x = 14.75:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
$\lim_{t \to 14.75^{+}} f(t) = 10$ .
$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

<h3>How to determinate the limit in a piecewise function</h3>

In a piecewise function, the limit for a given value exists when the two lateral limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.

According to the definition of lateral limit and by observing carefully the figure, we have the following conclusions:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
$\lim_{t \to 14.75^{+}} f(t) = 10$ .
$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

To learn more on piecewise function: brainly.com/question/12561612

#SPJ1

8 0

2 years ago