Answer:
a. 1/10 or 10%
b. 1/2 or 50%
Step-by-step explanation:
Since the combination of machines 1, 2 and 3 produce 100% of the total output when added together, then the probability of choosing a bolt at random that is defective is: 5 + 2 + 3 = 10% out of 100% or 10/100, which is 1/10 or 10%.
If the bolt that is choosen at random is defective, than the probability that it came from machine 1 is 5/10 or 1/2 which is also 50%.
QS would be 42. So the way i did it was I:
8x-51=3x-6
x=9
Plugged into both equations of QR and RS to then get the answer of 42
Answer:
t=11,11 days
Step-by-step explanation:
F=frogs poblation, t=time, be the variables dF/dt = KF, dF/F=Kdt, integrating
⇒ LnF=Kt+c,
; Knowing t=0, F=17 and t=6 F=51 (tripling every 6 days (17*3)),
⇒
, so
, now if F=130, t=? we have:

93 11/16 written as a decimal is 93.6875. Rounded it is approximately 93.7
I hope this helps:)