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3 years ago

6

Find the measure of x. SOMEONE PLEASE HELP

1 answer:

svet-max [94.6K]3 years ago

5 0

Answer should be 20

4x5=20

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Write a quadratic function, in standard form, that fits the set of points. Solve it as a system of three equations. (-4, 9), (0,

Tresset [83]

Answer:

$\boxed{y=2x^2+4x-7}$

Step-by-step explanation:

Let the quadratic function be

$y=ax^2+bx+c$

We substitute $(-4,9)$ into the equation to obtain;

$9=a(-4)^2+b(-4)+c$

$\Rightarrow 9=16a-4b+c---(1)$

We substitute $(0,-7)$ to obtain;

$-7=a(0)^2+b(0)^2+c$

$\Rightarrow c=-7---(2)$

We finally substitute $(1,-1)$ to obtain;

$-1=a(1)^2+b(1)^2+c$

$\Rightarrow -1=a+b+c---(3)$

We put equation (2) into equation (1) to get;

$9=16a-4b-7$

$16a-4b=16$

$\Rightarrow 4a-b=4---(4)$

$\Rightarrow -1=a+b-7$

$\Rightarrow a+b=6---(5)$

We add equation (4) and (5) to get;

$4a+a=6+4$

$\Rightarrow 5a=10$

$\Rightarrow a=2$

We put $a=2$ into equation (5) to get;

$2+b=6$

$\Rightarrow b=6-2$

$\Rightarrow b=4$

The reqiured quadratic function is

$y=2x^2+4x-7$

7 0

2 years ago

List the domain and range of the relation.<br> {(5,-5), (7,7), (0,-5), (7,1) (5,5)}

artcher [175]

Answer:

domain = (0,5,7)

range = (-5,1,5,7)

Step-by-step explanation:

domains are the x in (x,y) , and ranges are y in the (x,y) relations.

4 0

3 years ago

In quadratic formula

lorasvet [3.4K]

x² - x - 12 = 0

$x = \dfrac{-b \pm \sqrt{b^{2} - 4ac}}{2a}$

a = 1, b = -1, c = -12

$x = \dfrac{1 \pm \sqrt{(-1)^{2} - 4(1)(-12)}}{2(1)}$

x = 4 or -3

Answer: 4 or -3

4 0

3 years ago

G^4+ 5h<br> when g=2 & h=4

il63 [147K]

Answer: <em>36</em>

<em />

Step-by-step explanation:

<em>g^4+5h</em>

<em>2</em><em>^4+5(</em><em>4</em><em>)</em>

<em>16+20</em>

<em>36</em>

7 0

3 years ago

Find the coordinates of the third vertex that completes the construction of a right triangle on the coordinate plane.

Neko [114]

Answer:

<u>(7,a) Where a ∈ R - {7}</u>

<u>OR</u>

<u>(-2,a) where a ∈ R - {-2}</u>

Step-by-step explanation:

The coordinates of the given line from the right to the left are:

(7,1) and (-2,1)

So, to make a right triangle, we need to make a right angle or by another words, we need to a make a perpendicular line to the given line (i.e: a vertical line parallel to the y-axis at one of the given points)

So, the third vertex must be on the line x=7 or x=-2

So, the coordinates of the third vertex is:

<u>(7,a) Where a ∈ R - {7}</u>

<u>OR</u>

<u>(-2,a) where a ∈ R - {-2}</u>

3 0

3 years ago

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