You spent $10 on office supplies out of a $25 budget.What percent of your budget did you spend?

One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second

algol13

Answer:

Therefore the third container contains $\frac{735}{17}\%$ = 43.23 % acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

$= (V\times \frac{100+55}{100})$ cubic unit.

$=\frac{155}{100}V$ cubic unit.

The amount of acid in first container is

$=V\times \frac{25}{100}$ cubic unit.

$=\frac{25}{100}V$ cubic unit.

The amount of acid in second container is

$=(\frac{155}{100}V \times \frac{55}{100})$ cubic unit.

$=\frac{8525}{10000}V$ cubic unit.

Total amount of acid $=(\frac{25}{100}V+\frac{8525}{10000}V)$ cubic unit.

$=(\frac{2500+8525}{10000}V)$ cubic unit.

$=(\frac{11025}{10000}V)$ cubic unit.

Total volume of mixture $=(V+\frac{155}{100}V)$ cubic unit.

$=\frac{100+155}{100}V$ cubic unit.

$=\frac{255}{100}V$ cubic unit.

The amount of acid in the mixture is

$=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%$

$=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%$

$=\frac{735}{17}\%$

Therefore the third container contains $\frac{735}{17}\%$ acid.

5 0

3 years ago

How many triangles are there in a 7 sided shape

IceJOKER [234]

Answer:

There are five triangles in a heptagon. A heptagon is a seven-sided polygon.

Step-by-step explanation:

6 0

2 years ago

A $50 item was marked up 20%. What is the total increased cost of the item?

GenaCL600 [577]

They increased it by $10.

It ended up costing $60.

Hope this helps.

4 0

3 years ago

7. If the longer leg of a right triangle is twice as long as the shorter leg, what is the ratio of

kicyunya [14]

Answer: The ratio is 2.39, which means that the larger acute angle is 2.39 times the smaller acute angle.

Step-by-step explanation:

I suppose that the "legs" of a triangle rectangle are the cathati.

if L is the length of the shorter leg, 2*L is the length of the longest leg.

Now you can remember the relation:

Tan(a) = (opposite cathetus)/(adjacent cathetus)

Then there is one acute angle calculated as:

Tan(θ) = (shorter leg)/(longer leg)

Tan(φ) = (longer leg)/(shorter leg)

And we want to find the ratio between the measure of the larger acute angle and the smaller acute angle.

Then we need to find θ and φ.

Tan(θ) = L/(2*L)

Tan(θ) = 1/2

θ = Atan(1/2) = 26.57°

Tan(φ) = (2*L)/L

Tan(φ) = 2

φ = Atan(2) = 63.43°

Then the ratio between the larger acute angle and the smaller acute angle is:

R = (63.43°)/(26.57°) = 2.39

This means that the larger acute angle is 2.39 times the smaller acute angle.

5 0

3 years ago

4. Line t and AECA and AFDB are shown on the coordinate plane

julia-pushkina [17]

Answer:

A, B, C, E

Step-by-step explanation:

It can be seen from the figure that the points A, B, C and D, all are lying in the line t.

=> So that it can be concluded that AC and BC and BD have the slopes which are equal to each other and also equal to the slop of line t

So that all answer A, B, C are true.

In addition, as FD is parallel with x - axis, so that slope of the line t is equal to <em>tan angel FDB </em>

As FDB is the right triangle with BFD = 90°

=> tan angel FDB = FB/ FD (tan of an acute angel in the right triangle = opposite side/ adjacent side)

=> Slope of the line t is equal to FB/ FD

=> Answer E is true

6 0

3 years ago

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