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3 years ago

Please help! I can't seem to figure this stuff out...Final

Mathematics

1 answer:

Sonbull [250]3 years ago

3 0

Answer:

The answer is D

(0,-4)

Step-by-step explanation:

You might be interested in

What are 5 different equation that have x=5 as a solution.

777dan777 [17]

X+6=11
X-11=-6
5x=25
2x=10
2x+15=25

5 0

3 years ago

3^3x+1= 81 Solve the exponential function

Reil [10]

Answer:

x=1

Step-by-step explanation:

3^ (3x+1) = 81

Rewrite 81 as a power of 3

3^4

3^ (3x+1) = 3^4

Since the bases are the same, the powers are the same

3x+1 =4

Subtract 1 from each side

3x+1-1 =4-1

3x=3

Divide by 3

3x/3 = 3/3

x =1

8 0

3 years ago

If P = 2l + 2w, the formula to find w is . If P is 30 units and l is 10 units, w is units.

Helen [10]

Answer:

If P is 30 units and l is 10 units, w is 5 units

Step-by-step explanation:

1. Let's check the information given to resolve the question:

P = 2l + 2w

If P is 30 units and l is 10 units, w is units

2. Replacing with the values:

P = 2l + 2w

30 = 2 (10) + 2w

30 = 20 + 2w

-2w = 20 -30 (Subtracting 2w and - 30 to both sides)

-2w = - 10

2w = 10 (Multiplying by - 1 at both sides)

w = 5 (Dividing by 2 at both sides)

If P is 30 units and l is 10 units, w is 5 units

Note: Same answer than question 13938258

4 0

4 years ago

The value of y varies directly with the value of x. When y = 15, x = 3. What is the value of x when y = 60?

Viefleur [7K]

The answer is B
because at first y was equal to 15 and x equaled to 3 the quotient of 15/3 = 5.
now the y is 60 so, 60/5 = 12

6 0

3 years ago

Using the method of completing the square, put each circle into the form

tatiyna

Answer:

Standard form: $(x-\frac{1}{2})^2 + (y-0)^2 = 15$

Center: $(\frac{1}{2}, 0)$

Radius: $r =\sqrt{15}$

Step-by-step explanation:

The equation of a circle in the standard form is

$(x-h)^{2} + (y-k)^{2} = r^{2}$

Where the point (h, k) is the center of the circle

To transform this equation $4x^{2} -4x + 4y^{2} - 59 = 0$ this equation in the standard form we use the method of square.

First, we group similar variables

$(4x^{2} -4x) + (4y^{2}) - 59 = 0$

Divide both sides of equality by 4

$(x^{2} -x) + (y^{2}) - 14.75 = 0$

Now we complete square for variable x.

Take the coefficient "b" that accompanies the variable x and divide by 2. Then, elevate the result to the square:

$b =-1\\\\\frac{b}{2}= \frac{-1}{2}= -\frac{1}{2}\\\\(\frac{b}{2})^2= (-\frac{1}{2})^2 = \frac{1}{4}$

Now add $(\frac{b}{2})^2$ on both sides of the equality

$(x^{2} -x +\frac{1}{4}) + (y^{2}) - 14.75 = (\frac{1}{4})$

Factor the expression and simplify the independent terms

$(x-\frac{1}{2})^2 + (y^{2}) = 15$

$(x-\frac{1}{2})^2 + (y-0)^2 = 15$

Then

$h =\frac{1}{2}\\\\k=0$

and the center is $(\frac{1}{2}, 0)$

radius $r =\sqrt{15}$

3 0

3 years ago