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Zielflug [23.3K]
3 years ago
7

Express the limit as a definite integral on the given interval. lim n→[infinity] n xi ln(1 + xi2) Δx, [2, 7] i = 1

Mathematics
1 answer:
xenn [34]3 years ago
7 0

Answer:

Step-by-step explanation:

Consider \  the \ following \ series

\lim_{n \to \infty}  \sum \limits ^n_{i=1} x_i \ In ( 1+ x_i^2) \Delta x , [2,7]

Let's \ recall \ the \ explanation \  of definite \ integral \ in  \ terms  \ of  \ Riemann \ sum

\int^b_a \ f(x) \ dx =  \lim_{n \to \infty}  \sum \limits ^n_{i=1} \ f(x_i) \Delta x , \ where \ \Delta x = \dfrac{b-a}{n}

By  \ efinition,  \ the \  limit \   is \  then \  expressed \   as  \  integral

\lim_{n \to \infty} \sum ^a_{i=1} \ x_i \ In (1+x_i^2) \Delta x = \int^7_2 xIn (1+x^2) \ dx

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