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uysha [10]
3 years ago
14

Triangle ABC is similar to triangle PQR, as shown below:

Mathematics
2 answers:
Lena [83]3 years ago
7 0

Answer:

Step-by-step explanation:q/b=r/c

natita [175]3 years ago
3 0

Answer:

\frac{q}{b}=\frac{r}{c}

Step-by-step explanation:

Consider the options for this question are as follow,

  • \frac{q}{c}=\frac{r}{b}
  • \frac{c}{p}=\frac{b}{a}
  • \frac{c}{a}=\frac{q}{r}
  • \frac{q}{b}=\frac{r}{c}

Here, In triangles ABC and PQR,

AB = c, BC = a, AC = b, PQ = r, QR = p and PR = q,

Since,

\traingle ABC\sim \triangle PQR

We know that,

The corresponding sides of similar triangles are in same proportion,

Thus,

\frac{AB}{PQ}=\frac{BC}{QR}=\frac{AC}{PR}

\frac{c}{r}=\frac{a}{p}=\frac{b}{q}

\frac{r}{c}=\frac{p}{a}=\frac{q}{b}

\implies \frac{q}{b}=\frac{r}{c}

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Step-by-step explanation:

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The ratio of boys to girls is 14:17 if there are a total of 7626 students how many boys and how many girls are there ?
Finger [1]

Answer: 3444 boys, 4182 girls

Let there be 14x boys and 17x girls. Then there are 31x total students. Since 31x = 7626, x = 246. Then there are 14(246) = 3444 boys and 17(246) = 4182 girls.

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Alex777 [14]
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6 0
4 years ago
If angle U = 8x + 9 degrees, and angle W = 8x - 5 degrees, then the measure of angle U is ___ degrees.
PolarNik [594]

Answer:

m<U = 97^{o}

Step-by-step explanation:

From the given question, it can be observed that angles U and W are supplementary. These are angles that add up to 180^{o}.

So that;

<U + <W = 180^{o}

(8x + 9) + (8x - 5) = 180^{o}

16x + 4 = 180^{o}

16x = 180^{o} - 4

16 x = 176

x = \frac{176}{16}

  = 11^{o}

The measure of angle U = (8x + 9)

                                        = 8(11) + 9

                                        = 88 + 9

                                        = 97^{o}

Thus, the measure of angle U is 97^{o}.

8 0
3 years ago
∑∞ n=1 (n^2n)/(1+n)^(3n)
kvv77 [185]

Answer:

Given the series,

∑ ∞ n = 1 − 4 ( − 1 / 2 ) n − 1

I think the series is summation from n = 1 to ∞ of -4(-1/2)^(n-1)

So,

∑ − 4 ( − ½ )^(n − 1). From n = 1 to ∞

There are different types of test to show if a series converges or diverges

So, using Ratio test

Lim n → ∞ (a_n+1 / a_n)

Lim n → ∞ (-4(-1/ 2)^(n+1-1) / -4(-1/2)^(n-1))

Lim n → ∞ ((-4(-1/2)^(n) / -4(-1/2)^(n-1))

Lim n → ∞ (-1/2)ⁿ / (-1/2)^(n-1)

Lim n→ ∞ (-1/2)^(n-n+1)

Lim n→ ∞ (-1/2)^1 = -1/2

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Sum to infinity

Using geometric progression formula

S∞ = a / 1 - r

Where

a is first term

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So, first term is

a_1 = -4(-½)^1-1 = -4(-½)^0 = -4 × 1

a_1 = -4

Common ratio r = a_2 / a_1

a_2 = 4(-½)^2-1 = -4(-½)^1 = -4 × -½ = 2

a_2 = 2

Then,

r = a_2 / a_1 = 2 / -4 = -½

S∞ = -4 / 1--½

S∞ = -4 / 1 + ½

S∞ = -4 / 3/2 = -4 × 2 / 3

S∞ = -8 / 3 = -2⅔

The sum to infinity is -2.67 or -2⅔

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