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3 years ago

7

tiffany and justin have baseball card collections. justin has 36 more cards than tiffany if they have a total of 92 cards, how m

any does each have ?

1 answer:

saw5 [17]3 years ago

7 0

Answer:Tiffany has 28 Justin has 64

Step-by-step explanation:

64+28=92

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There are 6 blue marbles, 7 black marbles, 4 orange marbles, and 3 green marbles in a bag. Once a marble is drawn, it is replace

Aloiza [94]

Answer:

Step-by-step explanation:

step:- 1

The bag contains six blue marbles,seven black marbles , four orange marbles

and three green marbles

The total marbles contains in a bag 6+7+4+3=20

Two marbles can be drawn one after one with replacement

The total number of ways in which two cards drawn one after another with replacement

<h3>n(s) =20 $20 C_{1} X20 C_{1}=400$ </h3><h3>The no of favorable cases n(E)= $4C_{2} =\frac{4!}{4-2)!2!}$ </h3><h3>=6</h3><h3>Required probability P(E)= $\frac{n(E)}{n(S)} =\frac{4}{400} =\frac{1}{100}$ </h3>

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3 years ago

During a certain week, the mean price of gasoline in the New England region was $3.796 per gallon. A random sample of 32 gas sta

Ymorist [56]

Answer: the probability that the mean price for the sample was between $3.781 and $3.811 that week is 0.94122

Step-by-step explanation:

Given that;

sample size n = 32

mean μ = $3.796

standard deviation σ = 0.045

P(3.781 < x" < 3.811) = ?

Standard Error S.E = σ/√n = 0.045/√32 = 0.007955

z value for 3.781, z = x-μ/S.E = (3.781-3.796)/0.007955 = -1.8856 ≈ -1.89

z value for 3.811, z = x-μ/S.E = (3.811-3.796)/0.007955 = 1.8856 ≈ 1.89

P(3.781 < x" < 3.811) = P( -1.89 < z < 1.89)

= P(z < 1.89) - P(z < -1.89)

from z-score table

⇒ 0.9706 - 0.02938

⇒ 0.94122

Therefore the probability that the mean price for the sample was between $3.781 and $3.811 that week is 0.94122

6 0

3 years ago

HURRY!!! GIVING BRAINLIEST!!

Dima020 [189]

Try using a graphic calculator and then put the answer into the problem and it should make since, sorry

3 0

3 years ago

Ellen, a political intern, analyzes poll data for Cal Stegall, a candidate for state legislature. She notices Stegall's populari

Marizza181 [45]

The campaign manager is correct since other favorable events could have boosted Stegall's popularity after those speeches.

i just did the usa testprep thats the right answer

5 0

3 years ago

Read 2 more answers

Two rival companies began the same year. The equations below model the number of employees, y, at these companies x years after

aivan3 [116]

Answer:

Both the claims by the companies are not possible.

Step-by-step explanation:

Equations modeling number of employees 'y' after 'x' years of the start are,

For company R: y = 3x +24

For company T: y = 4x + 10

If Company R states that this year they have 42 employees,

42 = 3x + 24

3x = 42 - 24

x = $\frac{18}{3}$

x = 6 years

So company has completed 6 years this year.

Now we put x = 6 years in the equation for company T.

y = (4×6) + 10

y = 24 + 10

y = 34

Which doesn't match with the number of employees of the company R.

Therefore, claim of company R is not possible.

Company T stated that after 15 years they will have the same number of employees as company R.

For company T : y = 4(15) + 10

y = 70 employees

For company R : y = 3(15) + 10

y = 45 + 10

y = 55 employees

Therefore, claim of the company T is also not possible.

8 0

3 years ago