Answer:
Height of tree is 
<em>15 m.</em>
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Step-by-step explanation:
Given that student is 20 m away from the foot of tree.
and table is 1.5 m above the ground.
The angle of elevation is: 34°28'
Please refer to the attached image. The given situation can be mapped to a right angled triangle as shown in the image.
AB = CP = 20 m
CA = PB = 1.5 m
= 34°28' = 34.46°
To find TB = ?
we can use trigonometric function tangent to find TP in right angled 
Now, adding PB to TP will give us the height of tree, TB
Now, height of tree TB = TP + PB
TB = 13.72 + 1.5 = 15.22 <em>15 m</em>
LCM the last common multiple. the greatest common factor is the biggest number that will go into the 2 numbers so it can be no bigger than the 2 numbers. the LCM is larger than at least one of them
7cos(x) + 1 = 6sec(x)
7cos(x) + 1 = 6/cos(x)
7cos^(x) + cos(x) = 6
7cos^(x) + cos(x) - 6 = 0
[7cos(x) - 6][cos(x) + 1] = 0
cos(x) = 6/7 , x = arccos(6/7) and
cos(x) = -1, x = 180
First, put the numbers in order
A. 1,2,3,4,5,7,8,8,9.....median (middle number) is 5..when there is an odd number of data values, there will only be one median.
B. 14,14,15,16,17,18,19,20....if there is an even number of data points, there will be 2 middle numbers. In that case, u add the 2 middle numbers and divide by 2 to find the median. (16 + 17) / 2 = 33/2 = 16.5 is ur median.
