Linda. owed 8 lawns this week and earned $56. how much would Linda have earned if she had mowed 10 lawns?

Assume that the heights of boys in a high school basketball tournament are normally distributed, with mean 70 inches and standar

Annette [7]

Answer: 20

Step-by-step explanation:

We assume that the heights of boys in a high school basketball tournament are normally distributed.

Given : Mean height of boys : $\mu=70$ inches.

Standard deviation: $\sigma=2.5$ inches.

Let x denotes the heights of boys in a high school basketball tournament .

Then the probability that a boy is taller than 70 inches will be :-

$P(x> 70)=1-P(x\leq70)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{70-70}{2.5})\\\\=1-P(z\leq0)=1-0.5=0.5\ \ \text{[by using z-value table]}$

Now, the expected number of boys in a group of 40 who are taller than 70 inches will be :-

$40\times0.5=20$

Hence, the expected number of boys in a group of 40 who are taller than 70 inches=20

6 0

3 years ago

Please help !! I’m really stressed and soo confused

UkoKoshka [18]

36. NOTA

37. 456 mm

38. 510 oz

7 0

4 years ago

Solve the simultaneous equations.

Vera_Pavlovna [14]

Answer:

x = 1.5 ; y = -0.5

Step-by-step explanation:

2x + 4y = 1 ---------------------(i)

3x - 5y =7 ----------------------(ii)

(i) * 5 10x + 20y = 5

(ii)*4 12x -20y = 28

add, 22x = 33 { here y will be eliminated}

x = 33/22 = 3/2

x = 1.5

Put the value of x in equation (i)

2*1.5 + 4y = 1

3 + 4y = 1

4y = 1-3

4y = -2

y = -2/4 = -1/2

y = -0.5

4 0

3 years ago

Write a polynomial as the sum of the monomials and write it in standard form. For each of the above specify the degree of the re

klio [65]

Answer:

2b³ +2a -2c . . . . degree 3 polynomial

Step-by-step explanation:

The monomials are ...

... 4a . . . . degree 1 in a

... -5b·b² = -5b³ . . . . degree 3 in b

... -3c . . . . degree 1 in c

... 7b³ . . . . degee 3 in b (like term with -5b³)

... +c . . . . degree 1 in c (like term with -3c)

... -2a . . . . degree 1 in a (like term with 4a)

So, we have 3 pairs of like terms. The like terms can be combined by summing their coefficients.

The degree of the polynomial is that of the highest-degree term. (Here, the b³ term makes it a polynomial of degree 3.)

... 4a -2a = (4-2)a = 2a . . . . combining the "a" terms

... -5b³ +7b³ = (-5+7)b³ = 2b³ . . . . combining the b³ terms

... -3c +c = (-3 +1)c = -2c . . . . combining the "c" terms

In standard form, we write the highest-degree term first. Follwing terms are in order by decreasing degree. It is convenient, but perhaps not required, to then write the terms of the same degree in alphabetical order.

... = 2b³ +2a -2c . . . . a 3rd degree polynomial

7 0

3 years ago

For each pair of numbers, find a third whole number such that the three numbers form a pythagorean triple.

BabaBlast [244]

Answer:

Part 1) The third whole number is 44

Part 2) The third whole number is 40

Part 3) The third whole number is 25

Step-by-step explanation:

we know that

The Pythagoras theorem states that

In a right triangle

$c^{2} =a^{2} +b^{2}$

where

c is the greater length side

a and b are the legs

Case 1) we have

33,55

step a

Let

$a=33, b=55$

Find the value of c

$c^{2} =a^{2} +b^{2}$

$c^{2} =33^{2} +55^{2}$

$c^{2} =4,114$

$c =64.14$ ------> is not a whole number

step b

Let

$a=33, c=55$

Find the value of b

$b^{2} =c^{2} -a^{2}$

$b^{2} =55^{2} -33^{2}$

$b^{2} =1,936$

$b=44$

Case 2) we have

42,58

step a

Let

$a=42, b=58$

Find the value of c

$c^{2} =a^{2} +b^{2}$

$c^{2} =42^{2} +58^{2}$

$c^{2} =5,128$

$c =71.61$ ------> is not a whole number

step b

Let

$a=42, c=58$

Find the value of b

$b^{2} =c^{2} -a^{2}$

$b^{2} =58^{2} -42^{2}$

$b^{2} =1,600$

$b=40$

Case 3) we have

60,65

step a

Let

$a=60, b=65$

Find the value of c

$c^{2} =a^{2} +b^{2}$

$c^{2} =60^{2} +65^{2}$

$c^{2} =7,825$

$c =88.46$ ------> is not a whole number

step b

Let

$a=60, c=65$

Find the value of b

$b^{2} =c^{2} -a^{2}$

$b^{2} =65^{2} -60^{2}$

$b^{2} =625$

$b=25$

6 0

3 years ago