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2 years ago

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The entire graph of the function g is shown in the figure below.

1 answer:

marusya05 [52]2 years ago

7 0

The domain of the function is [-4, 4) and the range of the function is [-5, 2)

<h3>How to determine the domain and the range of the function?</h3>

<u>The domain</u>

As a general rule, it should be noted that the domain of a function is the set of input values or independent values the function can take.

This means that the domain is the set of x values

From the graph, we have the following intervals on the x-axis

x = -4 (closed circle)

x =4 (open circle)

This means that the domain of the function is [-4, 4)

<u>The range</u>

As a general rule, it should be noted that the range of a function is the set of output values or dependent values the function can produce.

This means that the range is the set of y values

From the graph, we have the following intervals on the y-axis

y = -5 (closed circle)

y = 2 (open circle)

This means that the range of the function is [-5, 2)

Read more about domain and range at:

brainly.com/question/10197594

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Which is equivalent to (2-5i)(-2+5i)

Nadusha1986 [10]

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alexgriva [62]

Answer:

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Step-by-step explanation:

49x² - 121

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The local public transport authority is conducting research into commuter behaviour. A previous census indicated that the mean c

kondor19780726 [428]

Answer:

$H_0:\mu = 45$ and $H_a:\mu < 45$

$T = 34.88$

The null hypothesis is not rejected

Step-by-step explanation:

Given

Random sample of 50 commuter times

Solving (a): The null and alternate hypothesis

From the question, a previous census shows that:

$\mu =45$ and $\sigma= 9.1$

This is the null hypothesis i.e.

$H_0:\mu = 45$

Reading further, a new test was to show whether the average has decreased.

This is the alternate hypothesis, and it is represented as:

$H_a:\mu < 45$

Solving (b) and (c): The test statistic (T).

This is calculated using:

$T = \frac{\mu}{\sigma/\sqrt n}$

In this case:

$n = 50$ $\mu =45$ and $\sigma= 9.1$

So:

$T = \frac{45}{9.1/\sqrt{50}}$

$T = \frac{45}{9.1/7.07}$

$T = \frac{45}{1.29}$

$T = 34.88$

Solving (c): Accept or reject null hypothesis

$\alpha = 0.05$

First calculate the degrees of freedom (df)

$df = n - 1 = 50 - 1$

$d f = 49$

From the t distribution table,

At: $d f = 49$ , $\alpha = 0.05$ and $T = 34.88$

the t score is:

$p = 1.676$

$p > 0.05$

<em>So, the null hypothesis is not rejected</em>

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2 years ago

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Musya8 [376]

Answer: SAS

Step-by-step explanation:

AC = AC (reflexive property)

So we know that AC = AC

Angle 1 = Angle 2 (given)

And AC = BC (given)

They are similar by SAS

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Tamiku [17]

40/100 simplify that and you will get .4.

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