DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
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Congruent shape</h3>
Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.
Given that DE = AB and BC = EF.
In right triangle DEF, using Pythagoras:
DF² = DE² + EF²
Also, In right triangle ABC, using Pythagoras:
AC² = AB² + BC²
But DE = AB and EF = BC, hence:
AC² = DE² + EF²
AC² = DF²
Taking square root of both sides, hence:
AC = DF
Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
Find out more on Congruent shape at: brainly.com/question/11329400
is the only acute angle whose sin = 1/2. Therefore, cos (
) =
Consider the converses:
a) If two planes have no points in common, then they are parallel. (true)
b) If a point lies on the y-axis, then it has x-coordinate 0. (true)
c) If two angles have the same measure, then they are congruent. (true)
d) If a figure has four sides, then it is a square. (FALSE) (A figure with 4 sides may not even be a plane figure.)
