(20*6)+(12*6)+(18*10)=312 500-312=188 colored pencil's left.
The quadrants are as follows:
The 1st quadrant has the points which have both x and y positive and the 3rd quadrant has the points which have both x and y negative. If the ordered pair and the same x and y value, if ons is positive, the other also is, and the same for negative.
So, at first we see that there are point where the x and y are the same and that are in the 1st or 3rd quadrant.
However, there is one special case:
When x and y are 0, that is, the ordered pair is (0, 0).
Since this point is the origin, it doesn't lie on any of the quadrants.
Thus, this affirmative is sometimes true. Every point but (0, 0) that have same x and y values are in the 1st or 3rd quadrant except for (0, 0).
Answer:
One unique triangle
Step-by-step explanation:
Answer:
<h2>
-29.61m/s</h2>
Step-by-step explanation:
Given the distance of fall of the student in term of the time t expressed by the equation s(t) = −16t² + 8√t, to get the average speed of fall of the pencil after 2.8 secs, we will need to differentiate the given function first since Velocity is the change in distance of a body with respect to time i.e
V = d(s(t))/dt
s(t) = −16t² + 8t^1/2
V = -32t+1/2(8)t^(1/2 - 1)
V = -32t+4t^-1/2
The average speed of the fall Using the fact that the pencil hit the ground in exactly 2.8 seconds, will be gotten by substituting t = 2.8 into the resulting equation.
V = -32t+4(2.8)^-1/2
V = -32t+4/√2.8
V = -32+4/1.6733
V = -32+2.391
v = -29.61m/s
<em>Hence the average speed of the fall is -29.61m/s</em>