Question

An airplane flies at an altitude of 14,690 ft while a submarine is submerged at a depth of 521 feet below the surface of the ocean.. What is the difference between these two elevations? Write an algebraic expression for the given applied problem. Simplified the algebraic expression. In the context of the applied problem, explain what your simplified algebraic expression represents.

Answer 1

Answer:

$d_{T} = d_{A}-d_{S}$. The algebraic equation represents the distance of the airplane with respecto to the submarine. The distance between the two elevations is 15211 feet.

Step-by-step explanation:

Let be $d$ the distance between a vehicle and sea level, $d > 0$ when vehicle is above sea level, otherwise is below sea level. The difference between airplane and submarine ($d_{T}$), measured in feet, is obtained by the following expression, that is:

$d_{T} = d_{A}-d_{S}$

Where:

$d_{A}$ - Distance of airplane with respect to sea level, measured in meters.

$d_{S}$ - Distance of submarine with respect to sea level, measured in meters.

If we know that $d_{A} = 14690\,ft$ and $d_{S} = -521\,ft$, then:

$d_{T} = 14690\,ft - (-521\,ft)$

$d_{T} = 15211\,ft.$

The algebraic equation represents the distance of the airplane with respecto to the submarine. The distance between the two elevations is 15211 feet.