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goblinko [34]
2 years ago
8

Each side of a square is increasing at a rate of 5 cm/s. At what rate (in cm2/s) is the area of the square increasing when the a

rea of the square is 49 cm2
Mathematics
2 answers:
pickupchik [31]2 years ago
5 0

Answer:

25 cm^2/sec

Step-by-step explanation:

I my understanding of the question.  It doesn't matter what the area of the square is currently is, for example if the area is 25 cm^2, 36 cm^2 or 49cm^2, the rate will ALWAYS increase by rate squared.

      rate(a)  x  rate(b)  =  rate(area)           in this case rate(a) = rate(b)

        (5 cm^2/s) (5 cm^2/s)  = 25 cm^2/s

nikklg [1K]2 years ago
4 0

Answer:

knkkl

Step-by-step explanation:

bjkjjjkhjhjhjkhjhj

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Pumps A, B, and C operate at their respective constant rates. Pumps A and B, operating simultaneously, can fill a certain tank i
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Answer:D) 1 hr

Step-by-step explanation:

Given

Pump A and B can fill tank in \frac{6}{5} hr

Pump A and C can fill tank in \frac{3}{2} hr

Pump B and C can fill tank in 2 hr

Let A be the total hr taken A therefore rate of A=\frac{1}{A} /hr

Let B be the total hr taken B therefore rate of B=\frac{1}{B} /hr

Let C be the total hr taken C therefore rate of C=\frac{1}{C} /hr

\frac{1}{A}+\frac{1}{B}=\frac{5}{6}-----1

\frac{1}{B}+\frac{1}{C}=\frac{1}{2}-----2

\frac{1}{A}+\frac{1}{C}=\frac{2}{3}-----3

Adding 1,2 & 3

2(\frac{1}{A}+\frac{1}{B}+\frac{1}{C})=\frac{5}{6}+\frac{1}{2}+\frac{2}{3}

\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=\frac{2}{2}

\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=1

thus time taken by A,B and C combined is 1 hr

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Step-by-step explanation:

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