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2 years ago

Find the slope of the line that goes through the two points. (6,7) (-2,11)

Mathematics

1 answer:

Alla [95]2 years ago

3 0

Answer:

-1/2

Step-by-step explanation:

The equation for slope is (y2-y1)/(x2-x1).

Plug in the values given in the problem

(11-7)/((-2)-6)

Then simplify

4/(-8)=-1/2

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9x + 26 + 7x - 17 = 2x + (-3x) + 5x 16x + 9 = 0 16x + 11 = 4x 16x + 9 = 4x

zzz [600]

Answer:

C. 16x+9=4x

Step-by-step explanation:

4 0

3 years ago

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What is the distance between the points (3, 5) and (3, 1)?

Aleksandr [31]

Answer:

Step-by-step explanation:

The x coordinate is the same so the distnce is only the difference in y

5 - 1 = 4

8 0

3 years ago

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D Evaluate arcsin (6)] at x = 4. dx

sineoko [7]

Answer:

$\frac{1}{2\sqrt{5} }$

Step-by-step explanation:

Let, $\text{sin}^{-1}(\frac{x}{6})$ = y

sin(y) = $\frac{x}{6}$

$\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})$

$\frac{d}{dx}\text{sin(y)}=\frac{1}{6}$

$\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}$ ---------(1)

$\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}$

cos(y) = $\sqrt{1-\text{sin}^{2}(y) }$

= $\sqrt{1-(\frac{x}{6})^2}$

= $\sqrt{1-(\frac{x^2}{36})}$

Therefore, from equation (1),

$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

Or $\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

At x = 4,

$\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}$

$\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}$

$=\frac{1}{6\sqrt{\frac{36-16}{36}}}$

$=\frac{1}{6\sqrt{\frac{20}{36} }}$

$=\frac{1}{\sqrt{20}}$

$=\frac{1}{2\sqrt{5}}$

4 0

3 years ago

Clare is painting some doors that are all the same size. She used 2 liters of paint to cover 135 doors. How many liters of paint

pashok25 [27]

Answer:

uhh 25%

Step-by-step explanation:

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3 years ago

1. Five friends share the cost of a dinner equally.

Nimfa-mama [501]

Hey there!

1a. Let c=cost of dinner, 5=the # of people, and P=the cost of person
P=C/5
b. P = (1000)/5 
P = 200

2a. For 1= 19, 2= 38, 57= and so on ( you just multiply the number of season by 19)
b. T= 19n

4 0

3 years ago