There is a straight angle witch mean that both b angles plus 88 equals 180 because a straight angel equals 180. So the solution would be D.
Answer:
16. D
17. 5^-1 · 5^-1 and 25^-1
8^0 · 8^3 and 8^3
Step-by-step explanation:
When you multiply two same numbers with exponents, just think of it as adding up exponents.
When you divide two same numbers with exponents, just think of it as subtracting exponents.
If a parenthesis has an exponent outside, then every exponent inside the parenthesis will be multiplied by that outside parenthesis.
(5^-1)^-2 · 5^3 ÷ 5^7
5^2 · 5^3 ÷ 5^7
5^5 ÷ 5^7
5^-2
When exponents are negative, you have to flip them or put them on the other side
5^-2 = 1/5^2 = 1/25
Let's try to find the equivalent pairs
6^7 ÷ 6^-2 = 6^5
6^9 = 6^5 Not equivalent
(6^3)^0 = 6
6^0 = 1 (Any number with a zero exponent is always 1)
1 = 6 Not equivalent
5^-1 · 5^-1 = 25^-1
5^-2 = 25^-1
Flip em
1/5^2 = 1/25
1/25 = 1/25 Equivalent
8^0 · 8^3 = 8^3
8^3 = 8^3 Equivalent
4^-3 ÷ 4^2 = 4^5
4^-5 = 4^5 Not equivalent
Answer: The zeroes are at (16,0) and (0,-16)
Step-by-step explanation:
Hello.
Question 4:
-2.34n = -12.168
Divide both sides by -2.34;
n = 5.2 is your answer to #4 (Answer choice "C.)"For Question 5:
-8c = 56
Divide both sides by -8 to solve for c;
c = -7 (remember your signs!) is your answer for #5 (Answer choice "C.)"
= -2; To solve for this, we need to multiply both sides by -12.168 to isolate and solve for our variable.

= -2; Multiply by -12.168
n = 24.336 (A negative multiplied by a negative results in a positive product.);
Your answer for #3 is n = 24.336 (Answer choice "B.)")I hope this helps!
Answer:
2587mm^3 approx!
Step-by-step explanation:
first you divide the nut into 6 part(in triangle now, by joining centre to each edge)
let's take one part of the triangular shape then area of that part can be found by using 1/2×base×height
i.e, 1/2×13×15=97.5(mm^2)
now when we consider depth of that traingular part,we will get volume of that part as area×depth
i.e, 97.5×6=585(mm^3)
now volume of all the 6 triangular part is 585×6=3510(in mm^3)
now take circular cavity in consideration, it's volume will be π(7^2)6=923(mm^3) approximately
now reqired volume will be volume of that hexagonal part minus that of circular cavity
=3510-923
=2587mm^3
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