First, let's get the area of the entire triangle since we'll need it later. The area of a triangle is A=1/2*b*h
We can find the height with the Pythagorean theorem by splitting the triangle in half.
3^2+b^2=6^2
9+b^2=36
b^2=27
b=√27
Then we can find the area:
A=1/2*6*√27
A=3√27 or =9√3 or 15.59
Now we can find the area of each region in the triangle other than the shaded region because they are all portions of a circle.
Each region has an angle of 60 because this is an equilateral triangle. Therefore the area of each region other than the shaded region will be 1/6 the area of a circle with a radius of 3 because a full circle is 360 degrees.
A=pi*r^2/6
A=pi*9/6
A=4.71
So three of these regions would have an area of 14.14
We do the area of the triangle minus the area of these regions to get the area of the shaded region
15.59-14.14 = 1.45
Hope this helps!
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Answer:
Step-by-step explanation:
Let the edge of the cube be a .
Given
Volume V = a³
= 3a² x 2
= 6a²
If a = 40 cm
= 9600 cm³/s .
Answer:
15
Step-by-step explanation:
Please correct me if I'm wrong
Answer:
(Explanation)
Step-by-step explanation:
Part A:
The graph of y = + 2 will be translated 2 units up from the graph of y = .
If you plug in 0 for x, you get a y-value of 2. The 2 is also not included with the , which is why it doesn't translate left.
This is what graph A should look like:
[Attached File]
Part B:
The graph of y = - 2 will be translated 2 units down from the graph of y = .
If you plug in 0 for x, you get a y-value of -2. The 2 is also not included with the , which is why it doesn't translate right.
This is what graph B should look like:
[Attached File]
Part C:
The graph of y = 2 is a stretched version of the graph y = . Numbers that are greater than 1 stretch and open up and numbers less than -1 stretch and open down.
This is what graph C should look like:
[Attached File]
Part D:
The graph of y = 
is a compressed version of the graph y = . Numbers that are in-between 0 and 1, and -1 and 0 are compressed.
This is what graph D should look like:
[Attached File]
