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d1i1m1o1n [39]
3 years ago
13

A meter is 100 centimeters. How many meters are equal to 712 centimeters?

Mathematics
2 answers:
Tanzania [10]3 years ago
6 0

Answer:

100×712 is equal to 71200

so the equality of 712 is 71200

Katyanochek1 [597]3 years ago
4 0

Answer:

7.12 meters

Step-by-step explanation:

So 1 meter = 100 centimeter

To find how many meters are in 712 centimeters, you have to divide 712 by 100.

\frac{712}{100} = 7.12

Therefore, 7.12 meters is equal to 712 centimeters.

<em>Hope this helps!!</em>

<em>- Kay :)</em>

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2 years ago
The sum of the measures of two adjacent angles is 72 degrees. The ratio of the smaller angle to the
Goryan [66]

Answer:

The larger angle is 54°

Step-by-step explanation:

Given

Let the angles be: θ and α where

θ > α

Sum = 72

α : θ = 1 : 3

Required

Determine the larger angle

First, we get the proportion of the larger angle (from the ratio)

The sum of the ratio is 1 + 3 = 4

So, the proportion of the larger angle is ¾.

Its value is then calculated as:.

θ = Proportion * Sum

θ = ¾ * 72°

θ = 3 * 18°

θ = 54°

4 0
3 years ago
Jia is skipping a rock across a pond. The sequence {4.2, 3.57, 3.0345, 2.5793, …} describes the height of the rock on each succe
mylen [45]

Answer:

u_n=4.2(0.85)^{n-1}

Step-by-step explanation:

u_1=4.2\\u_2=3.57\\u_3=3.0345\\u_4=2.5793

Geometric formula sequence:   u_n=ar^{(n-1)}

(where a is the first term of the sequence and r is the common ratio)

To find the common ratio, divide one of the terms by the previous term:

r=\frac{u_2}{u_1} =\frac{3.57}{4.2} =0.85

From inspection, a=4.2

Therefore, u_n=4.2(0.85)^{n-1}

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2 years ago
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By Green's theorem, the integral of \vec F along C is

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which is 6 times the area of D, the region with C as its boundary.

We can compute the integral by converting to polar coordinates, or simply recalling the formula for a circular sector from geometry: Given a sector with central angle \theta and radius r, the area A of the sector is proportional to the circle's overall area according to

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so that the value of the integral is

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