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PilotLPTM [1.2K]
3 years ago
7

3/4x + 2 = 3/8x - 4 X= Please show how u got ur answer

Mathematics
1 answer:
ch4aika [34]3 years ago
8 0

Answer:

Hope it helps u

Step-by-step explanation:

3/4x + 2 = 3/8x - 4

subtract 2 from both sides we get

(3/4)x=(3/8)x-6

subtract (3/8)x from both sides, we get

(3/4)x-(3/8)x= -6

now taking L.C.M we get

((6-3)/8)x= -6

(3/8)x= -6

x= -6*8/3

<h2>x= -16</h2>
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Nataliya [291]
Use substitution and substitute y into the other equation. One of the equations already gives you y in terms of x, so use that and substitute it into the other equation. y = 3x - 4

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-9x + 12 = -9x + 12
This is an identity. So that means that any value of x makes this equation true. So B.
8 0
3 years ago
Given the function f(x) = x3 + 2x2 − 3x − 5, what is resulting function when f(x) is shifted to the right 1 unit?
cluponka [151]
When shifted to the right 1 unit it would be:
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Aliza needs to run at a rate faster than 8.2 feet per second in order to exceed her fastest time in a race. After running for 15
Keith_Richards [23]

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a train travels 288km at a uniform speed.if the speed has been 4km per hour more it would have taken one hour less for the same
Lostsunrise [7]

Given:

A train travels 288 km at a uniform speed.

If the speed has been 4 km per hour more it would have taken one hour less for the same journey.

To find:

The initial speed of the train.

Solution:

Let x km/h be the initial speed on the train.

New speed of train = (x+4) km/h

We know that,

Time=\dfrac{Distance}{Speed}

Time taken by the train initially to cover 288 km is \dfrac{288}{x} hours.

New time taken by the train to cover 288 km is \dfrac{288}{x+4} hours.

It is given that If the speed has been 4 km per hour more it would have taken one hour less for the same journey.

\dfrac{288}{x}-\dfrac{288}{x+4}=1

\dfrac{288(x+4)-288x}{x(x+4)}=1

288x+1152-288x=x^2+4x

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Splitting the middle term, we get

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We know that the speed cannot be negative. So, the only possible value of x is 32.

Therefore, the speed of the train is 32 km/h.

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2 years ago
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