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I am Lyosha [343]
2 years ago
11

Please help !!! i don’t know how to write down the number of tiles :(

Mathematics
1 answer:
ICE Princess25 [194]2 years ago
3 0
Figure 0 has 3 tiles, 1 has 5, 2 has 7, 3 has 9, 4 has 11
You might be interested in
A building is 200ft long and 140 ft wide a 1/500 model is built of the building how long and how wide is the model?
Katena32 [7]
Let's start with the length. All you need to do is multiply is by 1/500.
You could also find the decimal equivalent to 1/500.
1/500= .002
200×.002= .4
So length of the model is .4 ft.
The width:
.002×140=.28
The width of the model is .28 ft.
The length of the model is .4 ft and the width of the model is .28 ft.

4 0
3 years ago
Help me find this please ASAP.........................
Likurg_2 [28]
Third one down



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5 0
3 years ago
What is the ratio for sin Y if tan Y = 8/15?
jeyben [28]

Answer: 8/17

Step-by-step explanation: The ratio for tangent is opposite/adjacent. The side opposite from Y has a length of 8, and the side next to it has a length of 15. These are the lengths of the legs of the triangle. To find the sine ratio, you need the hypotenuse.

The hypotenuse can be found using the Pythagorean theorem. 8^2=64 and 15^2=225. 225+64=289. The square root of 289 is 17. The hypotenuse has a length of 17.

The ratio for sine is opposite/hypotenuse. Take the value of the opposite from the tangent ratio (8) and the length of the hypotenuse (17) to get 8/17.

6 0
3 years ago
5. If ∆MNO = ∆SQR, which of the following is true? (1 point)
Brrunno [24]
Where are the following options?
4 0
3 years ago
Read 2 more answers
The diagonal of a rectangular swimming pool measures 29 yards. If the length of the pool is 25 yards, which measurement is close
nirvana33 [79]

Answer:

Width of the pool = 15 yards

Step-by-step explanation:

Given that:

Length of diagonal of swimming pool = 29 yards

Length of the pool = 25 yards

Let,

w be the width.

This will form a right angled triangle where the diagonal will be hypotenuse.

Using Pythagorean theorem;

(25)^2+(w)^2 = (29)^2\\625+w^2=841\\w^2= 841 - 625\\w^2 = 216

Taking square root on both sides

\sqrt{w^2}=\sqrt{216}\\w=14.70

Rounding off to nearest whole number

w = 15 yards

Hence,

Width of the pool = 15 yards

3 0
2 years ago
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