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BartSMP [9]
3 years ago
8

One metre of ribbon costs $0.45. If Tabitha buys 225 metres of ribbon, how much will she have to pay? (Please help me! I have to

turn it in in maximum 1 hour)
Mathematics
1 answer:
tatuchka [14]3 years ago
6 0

Answer: $101.25

Step-by-step explanation:

Since we are given the information that one metre of ribbon costs $0.45 and that Tabitha buys 225 metres of ribbon, the amount that she will have to pay will be gotten by multiplying the cost of one meter of ribbon by the total meters that she bought. This will be:

= $0.45 × 225

= $101.25

Therefore, the cost is $101.25

You might be interested in
(X squared+y squared)-(-x squared+y squared)
zmey [24]
X^2 + y^2 - x^2 +y^2

That would be (1x+1y)-(1x+1y)


8 0
3 years ago
Read 2 more answers
1. what is the period of the function f(x) shown in the graph?
ki77a [65]
Problem 1)

Answer: pi/2

-------------------------------

Place your pencil at (0,3) which is a good starting point, since x = 0 is often a good starting point. Trace along the curve until you reach back up at y = 3 again. So you'll go down and then back up until you reach (pi/2, 3). The difference in x values is pi/2-0 = pi/2. Every pi/2 units, the graph curve repeats itself over and over infinitely. 

Note: this is not the only way to determine the period. You can start at any point really. It helps to start at a min or max value, or at x = 0. In this case, it happened to be both. 

===========================================================
Problem 2)

Answer: See figure 2 (attached image)

-------------------------------

Point A is at (0,0)
Point B is at approximately (1.57,-2) which is exactly (pi/2,-2)

===========================================================
Problem 3)

Answer: See figure 3 (attached image)

===========================================================
Problem 4)

Answer: Choice B
The graph is horizontally compressed by a factor of 2 and shifts up 1 unit

-------------------------------

The jump from x to 2x will have the period go from 2pi to pi. The graph curve repeats itself more and more often (twice as often). Therefore we have an accordion squeeze effect going on, or think of it like a spring being pressed down. We have horizontal compression along the x axis.

Adding 1 to the end shifts every point upward 1 unit. Overall, this gives the visual the entire curve itself is shifted up 1 unit.

===========================================================
Problem 5)

Answer: f(x) = 5.05*sin((pi/12)x)+5.15

-------------------------------

max = 10.2
min = 0.1
difference = 10.2-0.1 = 10.1
Divide this difference in half: 10.1 = 5.05
So a = 5.05 is the amplitude

The period is T = 24 hrs since the height is 5.15 at midnight of one day, it rises and then falls and rises back to 5.15 by the next midnight
b = 2pi/T = 2pi/24 = pi/12
c = 0 since there is no phase shift in this sine function

d = 5.15 is the midline, which is the starting height at x = 0

f(x) = a*sin(bx-c)+d
f(x) = 5.05*sin((pi/12)x-0)+5.15
f(x) = 5.05*sin((pi/12)x)+5.15

===========================================================
Problem 6)

Answers are:
A) The max height of the Ferris wheel is 64 ft
B) The radius of the Ferris wheel is 30 ft

-------------------------------

The largest height of the table is 64, so 64 is the max height. This is why A is true.

B is true since the max is 64 and the min is 4, so 64-4 = 60 is the diameter, making the radius r = d/2 = 60/2 = 30

C is false because the height at t = 0 is 34 ft, but the lowest point is at height h = 4

D is false because the period is actually 10 seconds. Eg: going from t = 7.5 to t = 17.5 is a time of 10 seconds. During this time, the heights are 4, 34, 64, 34, 4 telling us that a full cycle has taken place.

===========================================================

4 0
3 years ago
{29, 29, 29, 28, 28, 27}
Kryger [21]
<h2>D is your answer</h2>

<h2><u>mean or median</u></h2>
3 0
3 years ago
How do i find LM? On number 2 .
Masja [62]
Given: KL is a tangent to the circle.
LM is another tangent to the circle.

We can use the tangent meeting at an external point theorem.
<em>Theorem</em>: <em>The tangent segments to a circle from an external point are equal.
</em>
Thus, we can say KL = LM, as they lie on a common circle, and are tangents to such circle.

4x - 2 = 3x + 3
4x - 3x = 3 + 2
x = 5

Since LM is 3x + 3, we can substitute the value of x to LM to render:
3(5) + 3 = 18

Thus, LM = KL = 18 units.
4 0
3 years ago
Find the missing length indicated ​
tiny-mole [99]

Answer:

x = 256

Step-by-step explanation:

Remark

Interesting question. Thanks for posting.

The small triangle has the height as the missing side.

Part One: Givens

a = 144

b = height = ?

c = 240

a^2 + b^2 = c^2

144^2 + b^2 = 240^2

20736 + b^2 = 57600                   Subtract 20736 from both sides

b^2 = 57600 - 20736

b^2 = 36864

√b^2 = √36864

b = 192

Solve for x

The relationship between the height (b) and 144 and x is

b^2 = 144 * x

36864 = 144x          Divide by 144

x = 256

5 0
3 years ago
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