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2 years ago

The circumference of the base of a cone is 24 inches. The slant height of the cone is 20 inches.

Mathematics

2 answers:

Tanzania [10]2 years ago

8 0

Answer: B. 384 square inches

Step-by-step explanation: Right on Edge 2022

loris [4]2 years ago

6 0

The surface area of a cone with circumference base of 24π inches and slant height of 20 inches is 384π inches² in terms of π.

<h3>Surface area of a cone</h3>

surface area = πr(r + l)

where

r = radius
l = slant height

Therefore,

l = 20 inches

24π = 2πr

r = 12

Therefore,

surface area = π(12)(12 + 20)

surface area = 12π(12 + 20)

surface area = 12π × 32

surface area = 384π inches²

learn more on surface area here: brainly.com/question/2847956

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3 years ago

How many thirds are equal to 2/6? please explain using an equation.

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Answer:

<u><em>How many thirds are equal to 2/6?</em></u>

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Step-by-step explanation:

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3 years ago

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Find the original price of a pair of shoes if the sale price is $168 after a 20% discount.

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Answer:

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Step-by-step explanation:

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2 years ago

Consider a roulette wheel consisting of 38 numbers 1 through 36, 0, and double 0. If Smith always bets that the outcome will be

Step2247 [10]

Answer:

The probability that Smith will lose his first 5 bets is 0.15

The probability that his first win will occur on his fourth bet is 0.1012

Step-by-step explanation:

Consider the provided information.

A roulette wheel consisting of 38 numbers 1 through 36, 0, and double 0. Smith always bets that the outcome will be one of the numbers 1 through 12,

It is given that Smith always bets on the numbers 1 through 12.

There are 12 numbers from 1 to 12.

Thus, the probability of success (winning) is= $\frac{12}{38}$

The probability of not success (loses) is= $1-\frac{12}{38}=\frac{26}{38}$

Part (A) Smith will lose his first 5 bets.

The probability that Smith loses his first 5 bets is,

$\frac{26}{38}\times\frac{26}{38}\times\frac{26}{38}\times\frac{26}{38}\times\frac{26}{38}=(\frac{26}{38})^5\approx0.15$

Hence, the probability that Smith will lose his first 5 bets is 0.15

Part (B) His first win will occur on his fourth bet?

Smith’s first win occurring on the fourth bet means that he loses the first 3 bets and wins on the fourth bet. That is,

$\frac{26}{38}\times\frac{26}{38}\times\frac{26}{38}\times\frac{12}{38}=(\frac{26}{38})^3\times\frac{12}{38}\approx0.1012$

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3 years ago

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