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Ber [7]
3 years ago
5

Please I need help ASAP

Mathematics
2 answers:
nata0808 [166]3 years ago
7 0

Answer:

i believe the answer is 52.4%

loris [4]3 years ago
3 0

Answer:

it is 52.4% I wish my math was this easy XD

Step-by-step explanation:

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Find the slope of the line (brainlist whoever gets it right first and extra points on this question)
nekit [7.7K]

Answer:

y = -3x

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What two rational expressions sum to 3x+4/x^2-6x+5?
Lubov Fominskaja [6]

Answer:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

Step-by-step explanation:

The given rational expression is:

\frac{3x+4}{x^{2}-6x+5} = \frac{3x+4}{(x-1)(x-5)}

We can use concept of Partial Fractions to solve this problem. Let,

\frac{3x+4}{(x-1)(x-5)}=\frac{A}{x-1} +\frac{B}{x-5}

Multiplying both sides by (x - 1)(x - 5), we get:

3x+4=A(x-5)+B(x-1)

Substituting x = 5, we get:

3(5)+4=A(5-5)+B(5-1)\\\\ 15+4=0+4B\\\\ 19=4B\\\\ B=\frac{19}{4}

Substituting x = 1, we get:

3(1)+4=A(1-5)+B(1-1)\\\\ 7=-4A\\\\ A=-\frac{7}{4}

Substituting the value of A and B, back in the original equation, we get:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

4 0
3 years ago
(4,-2) and (-2,-2) write the equation.​
bixtya [17]

the equation is Y=-2/3x+2/3

8 0
4 years ago
Answer answer it it it
lakkis [162]

Answer:

May-June

Step-by-step explanation:

Notice that:

● during April-May period the Badminton memberships rate of increase is greather then Swimming's since the graph of Badminton is showing a faster increase.

● During June-July period, both functions are decreasing so this period does not satisfy our condition.

● During May-June The Swimming memberships growed faster than Badminton's so its rate of increase is greather than Badminton's.

● during August-September period, The swimming memeberships are increasing slower than Badminton's

So the answer is May-June

8 0
4 years ago
Help me with this question please anybody
ehidna [41]

Answer:

  x = 19

Step-by-step explanation:

The work shown is almost complete. It can be finished by multiplying both sides of the equation by the inverse of the coefficient of x.

  x-coefficient: -1/3

  inverse of x-coefficient = 1/(-1/3) = -3

Then you have ...

  -3\left(-\dfrac{19}{3}\right)=-3\left(-\dfrac{1}{3}x\right)\\\\19=x\qquad\text{simplify}\\\\\boxed{x=19}

6 0
2 years ago
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