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3 years ago

Hello again. Can someone please help me with this as well. I'll give 100 points!

Mathematics

2 answers:

Aleks04 [339]3 years ago

8 0

Answer: Come on, don’t people learn these things in school!

Step-by-step explanation:

aev [14]3 years ago

6 0

Answer:

C. y ≤ 0

D. 18 bags of chips and 6 jars of salsa

Step-by-step explanation:

It is C because, it is over the x axis and it covers all the negative y's.

__________________________________________________________

2.5x + 4y ≤ 60

2.5(10) + 4(2) ≤ 60

25 + 8 ≤ 60

33 ≤ 60

It fits so A doesn't work

2.5x + 4y ≤ 60

2.5(20) + 4(2) ≤ 60

50 + 8 ≤ 60

58 ≤ 60

It fits so B doesn't work

2.5x + 4y ≤ 60

2.5(14) + 4(5) ≤ 60

35 + 20 ≤ 60

55 ≤ 60

It fits so C doesn't work

2.5x + 4y ≤ 60

2.5(18) + 4(6) ≤ 60

45 + 24 ≤ 69

It doesn't fit therefore, your answer would be D. 18 bags of chips and 6 jars of salsa.

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3 years ago

What two rational expressions sum to 3x+4/x^2-6x+5?

Lubov Fominskaja [6]

Answer:

$\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}$

Step-by-step explanation:

The given rational expression is:

$\frac{3x+4}{x^{2}-6x+5} = \frac{3x+4}{(x-1)(x-5)}$

We can use concept of Partial Fractions to solve this problem. Let,

$\frac{3x+4}{(x-1)(x-5)}=\frac{A}{x-1} +\frac{B}{x-5}$

Multiplying both sides by (x - 1)(x - 5), we get:

$3x+4=A(x-5)+B(x-1)$

Substituting x = 5, we get:

$3(5)+4=A(5-5)+B(5-1)\\\\ 15+4=0+4B\\\\ 19=4B\\\\ B=\frac{19}{4}$

Substituting x = 1, we get:

$3(1)+4=A(1-5)+B(1-1)\\\\ 7=-4A\\\\ A=-\frac{7}{4}$

Substituting the value of A and B, back in the original equation, we get:

$\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}$

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3 years ago