Answer:
is the equation of this parabola.
Step-by-step explanation:
Let us consider the equation
![\mathrm{Range\:of\:}-4x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:0]\end{bmatrix}](https://tex.z-dn.net/?f=%5Cmathrm%7BRange%5C%3Aof%5C%3A%7D-4x%5E2%3A%5Cquad%20%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Af%5Cleft%28x%5Cright%29%5Cle%20%5C%3A0%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%2C%5C%3A0%5D%5Cend%7Bbmatrix%7D)
As
Therefore, the parabola vertex is
so,
Therefore, is the equation of this parabola. The graph is also attached.
Whatever number is the exponent if negative just move it to the right how much the number is. if it 5 with an exponent of -3 then you just move the decimal point 3 times to the right. The anwer to that question would be .005
Given : - Square ABCD with side 3. E and F as midpoints.
To find : - area of EBFD
Solution : - We have, area of square ABCD = 3 x 3 = 9 units.
Thus, (ar)EBFD = ar ABCD - ar DAE - arDCF
arDAE = 1/2 x base x height
=1/2 x 1.5 x 3 ( AE is 1/2 of AB = 1.5, DA is altitude)
= 2.25
arDFC = 1/2 x base x height
= 1/2 x 1.5 x 3 (FC is 1/2 of BC, DC is altitude)
= 2.25
Thus, (ar) EBFD = arABCD - arDAE - arDCF
= 9 - 2.25 - 2.25
= 4.5 units.
Thus, area of quad EBFD is 4.5 units.
Ok i tried and ig youre looking for what a and b equal for both systems..... it'll be 1) a=-2b+15 b=7.5-(1/2)a <-- fraction........2) a=-6+b b=6-a
