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3 years ago

12

A house has decreased in value by 34% since it was purchased. If the current value is $231,000, what was the value when it was p

urchased?

1 answer:

GenaCL600 [577]3 years ago

5 0

Answer:

309,540

Step-by-step explanation:

231,000 + 34%

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you are building a sand castle and want to use a cylindrical bucket that holds 885 cubic inches of sand. if the bucket has a hei

natulia [17]

885/11.7=75.64/3.14=24.09=square root of 24.09=4.9

4 0

3 years ago

Simplify. 4 × (8 + 5) + 9 45 46 61 62

Darya [45]

Answer:

61

Step-by-step explanation:

4 × (8 + 5) + 9

Parentheses first

4 × (13) + 9

Then multiply

52 +9

Then add

61

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2 years ago

Given a+b=7 and a–b=3, find:<br><br> 2^a*2^b

seropon [69]

Answer:

128

Step-by-step explanation:

5+2=7

5-2=3

2^5=32

2^2=4

32*4=128

Hope this helps:)

7 0

3 years ago

Solve the equation. d-5/9=3/9

Aleks04 [339]

Answer:

d = 8/9

Step-by-step explanation:

All you have to do is add 5/9 to both sides.

d - 5/9 + 5/9 = 3/9 + 5/9

d = 89

So, d = 8/9.

8 0

3 years ago

A family wants to save for college tuition for their daughter. What continuous yearly interest rate r% is needed in their saving

sergey [27]

Answer:

The continuous yearly interest is 22.5% per year.

Step-by-step explanation:

Continuous yearly interest:

Continuous yearly interest is defined as the sum of the interest comes from principle and the interest comes from interest.

The formula for continuous interest yearly is

$A=Pe^{rt}$

where A = The final amount =$110,000

P= principle =$4,700

r= rate of interest

t= time (in year)= 14 years

$\therefore 110,000= 4,700e^{r\times 14}$

$\Rightarrow e^{14r}= \frac{110,000}{4,700}$

Taking ln both sides

$\Rightarrow ln e^{14r}= ln(\frac{110,000}{4,700})$

$\Rightarrow {14r}= ln(\frac{1100}{47})$

$\Rightarrow r=\frac{ln( \frac{1100}{47})}{14}$

$\Rightarrow r = 0.225$ (approx)

The continuous yearly interest is 0.225 = 22.5% per year.

4 0

3 years ago