Answer:
The correct answers are a. Independent; b. Independent; c. Independent; e. Not Independent
Step-by-step explanation:
a. A jar contains fifteen coins which. Two coins are picked randomly without replacement. Thus the second pick is not dependent on the first pick as the coins in the all same and thus the experiment is independent.
b. A number cube is rolled twice. Outcome of the first roll is independent of the outcome in the second and thus the experiment is independent.
c. A box contains number cards labeled from 1 to 10 where 2 cards are chosen randomly with replacement. Hence first draw does not effect the sample making the experiment independent.
e. There are 3 green balls and 7 red balls in a bag with 2 balls are chosen randomly without replacement. Thus one pick depends on what is drawn in the previous pick thus making it a dependent or not independent event.
Multiply the first equation by -2 gives:_
-2y = -8 + 2x
2y = 8 - 2x
adding these 2 equations:-
0 = 0
This shows that the 2 equations are equal so there are infinite solutions
Answer:
Step-by-step explanation:
a1=2/3
sequence is 2/3,3/4,4/5,...
for numerator a1=2
d=3-2=1
numerator of nth term=a1+(n-1)d=2+(n-1)×1=2+n-1=n+1
denominator = 1 more than numerator=n+1+1=n+2
so an=(n+1)/(n+2)
or for denominator a1=3,d=4-3=1
denominator of nth term=3+(n-1)×1=3+n-1=n+2
an=(n+1)/(n+2)
Step-by-step explanation:
X+100=180(linear pair)
X=180-100
X=80
30+y+x=180(sum of angle of triangle)
Y=180-110
Y=70
<span>The graph you plotted is the graph of f ' (x) and NOT f(x) itself. </span>
Draw a number line. On the number line plot x = 3 and x = 4. These values make f ' (x) equal to zero. Pick a value to the left of x = 3, say x = 0. Plug in x = 0 into the derivative function to get
f ' (x) = (x-4)(6-2x)
f ' (0) = (0-4)(6-2*0)
f ' (0) = -24
So the function is decreasing on the interval to the left of x = 3. Now plug in a value between 3 and 4, say x = 3.5
<span>f ' (x) = (x-4)(6-2x)
</span><span>f ' (3.5) = (3.5-4)(6-2*3.5)
</span>f ' (3.5) = 0.5
The function is increasing on the interval 3 < x < 4. The junction where it changes from decreasing to increasing is at x = 3. This is where the min happens.
So the final answer is C) 3
