All categories

3 years ago

Please help I only have a short amount of time to get my grades up

Mathematics

2 answers:

4vir4ik [10]3 years ago

8 0

Answer:

It is A

Step-by-step explanation:

Hope this helped have an amazing day/month/year!

omeli [17]3 years ago

5 0

Step-by-step explanation:

the first option is the correct answer.

You might be interested in

Anything will help please

svp [43]

The way that I memorised how to do sin, cos, and tan is by the following: SOH, CAH, TOA

SOH = Sin is OPPOSITE / HYPOTENUSE

CAH = Cos is ADJACENT / HYPOTENUSE

TOA = Tan is OPPOSITE / ADJACENT

For example if we were to solve question 5

Sin T = 6 root 2 / 19

Cos T = 17 / 19

Tan T = 6 root 2 / 17

Repeat the steps for question 6

For the rest of the questions (7,8,9) you have to take the information given and figure out if you should us Sin, cos, or Tan. then plug the numbers in the calculator and while doing sin ^ -1, cos ^ -1, tan ^ -1

for example on question 7, to find the angle x they have given you the hypotenuse and the adjacent side so

cos x = 9 / 18

to find x plug: cos^-1 (9/18) in the calculator

8 0

2 years ago

Find the area of the circle

andrezito [222]

Answer:

A=103.13cm

Step-by-step explanation:

Formula: A= c^2/4π (C being the circumference and ^2 means it's squared)

Plug in what you know: 36^2/4π

1296/4π= 103.13

4 0

3 years ago

The rectangular prism below has a base area of 44.3 units2 and a volume of 221.5

Natasha_Volkova [10]

<h3>Given:</h3>

$base \: area = 44.3 \: {units}^{2}$

$volume = 221.5 \: {units}^{3}$

the height of the given rectangular prism.

<h3>Solution:</h3>

$volume= base \: area \times height$

$height = \frac{volume}{base \: area}$

$height = \frac{221.5}{44.3}$

$height = 5 \: units$

Therefore, the height of the given rectangular prism is 5 units.

8 0

2 years ago

Read 2 more answers

I need help fast please

GenaCL600 [577]

Answer:

The answer is 540 mm^3

Step-by-step explanation:

using v= BH

v= 30×18

v= 540mm^3

pls like and follow, hope this helps.:-):-)

3 0

2 years ago

∫(cosx) / (sin²x) dx

kirza4 [7]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2822772

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx}\\\\\\
=\mathsf{\displaystyle\int\! \frac{1}{(sin\,x)^2}\cdot cos\,x\,dx\qquad\quad(i)}$

Make the following substitution:

$\mathsf{sin\,x=u\quad\Rightarrow\quad cos\,x\,dx=du}$

and then, the integral (i) becomes

$=\mathsf{\displaystyle\int\! \frac{1}{u^2}\,du}\\\\\\
=\mathsf{\displaystyle\int\! u^{-2}\,du}$

Integrate it by applying the power rule:

$\mathsf{=\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\
\mathsf{=\dfrac{u^{-1}}{-1}+C}\\\\\\
\mathsf{=-\,\dfrac{1}{u}+C}$

Now, substitute back for u = sin x, so the result is given in terms of x:

$\mathsf{=-\,\dfrac{1}{sin\,x}+C}\\\\\\
\mathsf{=-\,csc\,x+C}$

$\therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx=-\,csc\,x+C} \end{array}}\qquad\quad\checkmark$

I hope this helps. =)

Tags: indefinite integral substitution trigonometric trig function sine cosine cosecant sin cos csc differential integral calculus

5 0

4 years ago