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Elena-2011 [213]
1 year ago
12

Anything will help please

Mathematics
1 answer:
svp [43]1 year ago
8 0

The way that I memorised how to do sin, cos, and tan is by the following: SOH, CAH, TOA

SOH = Sin is OPPOSITE / HYPOTENUSE

CAH = Cos is ADJACENT / HYPOTENUSE

TOA = Tan is OPPOSITE / ADJACENT

For example if we were to solve question 5

Sin T = 6 root 2 / 19

Cos T = 17 / 19

Tan T = 6 root 2 / 17

Repeat the steps for question 6

For the rest of the questions (7,8,9) you have to take the information given and figure out if you should us Sin, cos, or Tan. then plug the numbers in the calculator and while doing sin ^ -1, cos ^ -1, tan ^ -1

for example on question 7, to find the angle x they have given you the hypotenuse and the adjacent side so

cos x = 9 / 18

to find x plug: cos^-1 (9/18) in the calculator

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3 years ago
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8 0
2 years ago
An isosceles triangle has an angle that measures 38degrees. What measures are possible for the other two angles? Choose all that
Sphinxa [80]

Answer:

  • 71° and 71°.

⠀

Step-by-step explanation:

The triangle having two sides equal along with one different side is called an isosceles triangle.

⠀

  • So, Let us assume the other sides (two equal sides) of the isosceles triangle as x. As the different side is already given in the question.

⠀

We know that,

  • The sum of all angles of a triangle is 180°

⠀

So, According to the question :

⠀

{\longrightarrow \it\qquad { \ { {  38 \: }^{ \circ}   + x + x  =  180{}^{ \circ} }}}

⠀

{\longrightarrow \it\qquad { \ { {  38 \: }^{ \circ}   + 2x   =  180{}^{ \circ} }}}

⠀

{\longrightarrow \it\qquad { \ {   2x   =  180{}^{ \circ} - {  38 \: }^{ \circ}}}}

⠀

{\longrightarrow \it\qquad { \ {   2x   =  142{}^{ \circ}  }}}

⠀

{\longrightarrow \it\qquad { \ {   x   =    \dfrac{142{}^{ \circ}}{2}   }}}

⠀

{\longrightarrow \it\qquad { \pmb {   x   =  71^{ \circ}  }}}

⠀

Therefore,

  • The measure of the two other angles of the isosceles triangle are 71° and 71°.
3 0
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