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zzz [600]
3 years ago
12

Pls help me find the answer

Mathematics
1 answer:
gavmur [86]3 years ago
3 0

Answer:

The answer is D

Step-by-step explanation:

I took the test

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-6m+5p+7+8m-10<br> Help me
nikklg [1K]

Answer:

add like terms the simplified answer is 2m+5p-3

Step-by-step explanation:

lmk if it is not supposed to be simplified

4 0
3 years ago
Read 2 more answers
. 40% of 60 students of a class are good at art. How many students are not good at art? *​
melisa1 [442]

Answer:

36

Step-by-step explanation:

1-40% = 1-0.4=0.6 or 60%

60% not good at art.

60*60% = 60*6/10 = 6*6 = 36

6 0
2 years ago
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Please help, it’s urgent !
g100num [7]

Answer:

f(-10) = 2 times -10 + 1

= -19

f(2) = 2^2

= 4

f(-5) = 2 times -5 + 1

= -9

f(-1) = (-1)^2

= 1

f(8) = 3-8

= -5

Step-by-step explanation:

5 0
3 years ago
Solve the equation √x-6 +2=6
Dovator [93]

Answer:

x = 22

Step-by-step explanation:

\sqrt{x-6} + 2 = 6 ( subtract 2 from both sides )

\sqrt{x-6} = 4 ( square both sides to clear the radical )

x - 6 = 4² = 16 ( add 6 to both sides )

x = 22

8 0
2 years ago
In a right triangle ΔABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find: Chapter Reference b The length of the
Butoxors [25]

Answer:

The length of the angle bisector of angle ∠A is 6.01.

Step-by-step explanation:

It is given that length of leg AC = 5 ft and the hypotenuse AB = 13 ft.

Using pythagoras theorem

(AB)^2=(BC)^2+(AC)^2

(13)^2=(BC)^2+(5)^2

169=(BC)^2+25

BC=12

\sin A=\frac{\text{perpendicular}}{\text{hypotenuse}}

\sin A=\frac{BC}{AB}

A=\sin ^{-1}\frac{12}{13}

A=67.38

Bisector divides the angle in two equal parts, therefore,

A'=\frac{67.38}{2} =33.69

In triangle ACD.

\cos A'=\frac{\text{Base}}{\text{Hypotenuse}}

\cos A'=\frac{AC}{AD}

\cos (33.69^{\circ})=\frac{5}{AD}

0.832=\frac{5}{AD}

AD=\frac{5}{0.832} =6.009\approx 6.01

Therefore the length of the angle bisector of angle ∠A is 6.01.

4 0
3 years ago
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