An amusement park has two merry-go-rounds. The first merry-go-round has a platform with a diameter of 13 meters and the second m erry-go-round has a platform with a radius of 9.5 meters. How much larger is the area of the larger merry-go-round’s platform compared to the area of the smaller merry-go-round’s platform? Round to the nearest whole number. Show your work. (Use Pi = 3.14)
1 answer:
Answer:
<em>The larger merry-go-round's platform is </em><u> 151m² </u><em> larger than the smaller merry-go-round's platform. </em>
Explanation:
The<em> area </em>of a round shape is equal to the area of a circle.
The formula for the area of a circle is:
Then, use that formula for each merry-go-round.
<em><u>1. First merry-go-round</u></em>
<em />
radius = diameter / 2 = 13m / 2 = 6.5m area = π (6.5m)² = 3.14 × (6.5m)² = 132.665m²
<em><u>2. Second merry-go-round</u></em>
area = π (9.5m)² = 3.14 × (9.5m)² = 283.385m² <u />
<u>3. Difference of the areas</u>
<u />
Larger area - smaller area = 283.385m² - 132.665m² = 150.72m²
Round to the nearest whole number: 151m².
Hence, the larger merry-go-round's platform is 151m² larger than the smaller merry-go-round's platform.
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