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Varvara68 [4.7K]
3 years ago
8

An amusement park has two merry-go-rounds. The first merry-go-round has a platform with a diameter of 13 meters and the second m

erry-go-round has a platform with a radius of 9.5 meters. How much larger is the area of the larger merry-go-round’s platform compared to the area of the smaller merry-go-round’s platform? Round to the nearest whole number. Show your work. (Use Pi = 3.14)
Mathematics
1 answer:
Zinaida [17]3 years ago
3 0

Answer:

  • <em>The larger merry-go-round's platform is </em><u>   151m²   </u><em> larger than the smaller merry-go-round's platform.</em>

Explanation:

The<em> area </em>of a round shape is equal to the area of a circle.

The formula for the area of a circle is:

  • Area = π × radius²

Then, use that formula for each merry-go-round.

<em><u>1. First merry-go-round</u></em>

<em />

  • diameter = 13m
  • radius = diameter / 2 = 13m / 2 = 6.5m
  • area = π (6.5m)² = 3.14 × (6.5m)² = 132.665m²

<em><u>2. Second merry-go-round</u></em>

  • radius =9.5m
  • area = π (9.5m)² = 3.14 × (9.5m)² = 283.385‬m²

<u />

<u>3. Difference of the areas</u>

<u />

  • Larger area - smaller area = 283.385m² - 132.665m² = 150.72m²

  • Round to the nearest whole number: 151m².

Hence, the larger merry-go-round's platform is 151m² larger than the smaller merry-go-round's platform.

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