Question

Under certain conditions, the substance calcium carbonate can be broken down to form calcium oxide and carbon dioxide. If 31.7 grams of calcium carbonate react to form 17.8 grams of calcium oxide, how many grams of carbon dioxide must simultaneously be formed

Answer 1

Answer:

$13.93\ \text{g}$

Explanation:

Molecular weight of $CaCO_3$ = 100.0869 g/mol

Mass of $CaCO_3$ = 31.7 g

Moles of $CaCO_3$ = $\dfrac{31.7}{100.0869}=0.3167\ \text{mol}$

Moles of both $CaO$ and $CO_2$ is $0.3167\ \text{mol}$

Molecular weight of $CO_2$ = 44 g/mol

Mass of $CO_2$ = $44\times 0.3167=13.93\ \text{g}$

The mass of carbon dioxide formed simultaneously is $13.93\ \text{g}$.