Question

The coordinates of the vertices of quadrilateral ABCD are A(0, −4) , B(−4, 3) , C(3, 4) , and D(6, −1) . Drag and drop the choices into each box to correctly complete the sentences. The slope of AB¯¯¯¯¯ is , the slope of BC¯¯¯¯¯ is , the slope of CD¯¯¯¯¯ is , and the slope of AD¯¯¯¯¯ is . Quadrilateral ABCD is because .

Answer 1

Answer:

The slope of AB is -7/4, the slope of BC is 1/7 , the slope of CD is 5/3, and the slope of AD is 2. So, Quadrilateral ABCD is neither a parallelogram nor a trapezoid because neither pair of opposite sides are parallel.

Step-by-step explanation:

Since, a quadrilateral having,

One pair of parallel opposite sides is Trapezoid,

While, having two pair of parallel opposite sides is parallelogram.

Since, the slope of a line segment having the end points $(x_1, y_1)$ and $(x_2, y_2)$ is,

$m=\frac{y_2-y_1}{x_2-x_1}$

Here, the vertices of the quadrilateral ABCD are A(0, −4) , B(−4, 3) , C(3, 4) , and D(6, −1),

Slope of AB = $\frac{3+4}{-4-0}=-\frac{7}{4}$

Slope of BC = $\frac{4-3}{3+4}=\frac{1}{7}$

Slope of CD = $\frac{-1-4}{6-3}=-\frac{5}{3}$

Slope of AD = $\frac{-1+4}{6-0}=\frac{3}{6}=2$

Hence, Quadrilateral ABCD is neither a parallelogram nor a trapezoid because neither pair of opposite sides are parallel.

Answer 2

Answer:

AB -7/4, BC 1/7, CD -5/3, and AD 1/2

neither a parallelogram nor a trapezoid because

neither pair of opposite sides are parallel

Step-by-step explanation: