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3 years ago

Pls help I will give u 10 points

Mathematics

2 answers:

Alex_Xolod [135]3 years ago

7 0

It is correct
One room per day. Nine rooms in nine days

lesya692 [45]3 years ago

6 0

Answer:

1. isn't

2. 0.5 or 1/2

3. 9x0.5=4.5 or 9/2

You can do this... it's easy stuff. You got it!

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How do you do question b?

notsponge [240]

Part (b)

We use the result of part (a) and plug in (x,y) = (0,0). This is directly from the initial condition y(0) = 0.

$\arcsin(4y) = x^2 + C\\\\\arcsin(4*0) = (0)^2 + C\\\\\arcsin(0) = C\\\\0 = C\\\\C = 0\\\\$

-----------------

This means,

$\arcsin(4y) = x^2 + C\\\\\arcsin(4y) = x^2 + 0\\\\\arcsin(4y) = x^2\\\\4y = \sin(x^2)\\\\y = \frac{1}{4}\sin(x^2)\\\\$

is the solution with the initial condition y(0) = 0.

6 0

3 years ago

Solve. (x + 3)^1/2– 1 = x

Natali [406]

Answer:

x=1

Step-by-step explanation:

$(x + 3) ^{ \frac{1}{2} } - 1 = x \\ \sqrt{x + 3} - 1 = x \\ \sqrt{x + 3} = x + 1 \\ square \: both \: sides \\ x + 3 = {x}^{2} + 2x + 1 \\ {x}^{2} + 2x - x + 1 - 3 = 0 \\ {x}^{2} + x - 2 = 0 \\ x ^{2} + 2x - x - 2 = 0 \\ (x^{2} + 2x) - (x + 2) = 0 \\ x(x + 2) - 1( x + 2) = 0 \\ (x - 1)(x + 2) = 0 \\ x - 1 = 0 \\ x = 1 \\ \\ \\ x + 2 = 0 \\ x = - 2$

8 0

3 years ago

Solve the following equation: lim x->0 sin3x/5x^3-4x.

goblinko [34]

Usual limit of sin is sinX/X--->1, when X--->0

sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x= [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
=(sin3x / 3x) . (3/5x^2- 4)
finally lim sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
x----->0 x---->0

3 0

3 years ago

HELPPP PLSSS

Anastaziya [24]

First place: Liz
Faster: Amanda
Longest time: Steve

4 0

3 years ago

Read 2 more answers

Select the ordered pairs that are solutions to the inequality

sveticcg [70]

Answer:

I would say equal to twelve

Step-by-step explanation:

Hope this helps.

5 0

3 years ago