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Nostrana [21]
3 years ago
9

What is the slope of the line given the two points: (-4, -4) (-1, 14)

Mathematics
2 answers:
pychu [463]3 years ago
6 0
The slope is 6 I took the test
ivanzaharov [21]3 years ago
3 0

Answer:

6

Step-by-step explanation:

Do rise over run (change in y over change in x)

\frac{18}{3} = 6

The slope is 6

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What would be the answer for 24y =7
Marta_Voda [28]

Answer:

y=\frac{7}{24}

Step-by-step explanation:

24y = 7

Our primary objective here is to get y on it's own side, without any numbers attached.

Since a 24 is attached to the y, we have to divide the 24y by 24.

24y=7

\frac{24y}{24} = \frac{7}{24}

Remember that whatever we do to one side, we MUST do to the other.

y=\frac{7}{24}

Since \frac{7}{24} can't be simplified, that would be our answer.

Please let me know if you need help with anything else. :)

5 0
3 years ago
Roots of Quadratics 50 PTS!!!
noname [10]

The values of k for the different quadratic equation solutions are as follows

a  the equation 2x² - x + 3k = 0 has two distinct real roots

  • k < 1/24

b. the equation 5x² - 2x + (2k − 1) = 0 has equal roots

  • k = 3/5

ci the equation -x² + 3x + (k + 1) = 0 has real roots

  • k > -3.25

d the equation 3kx² - 3x + 2 = 0 has no real solutions

  • k < ± 1.633

<h3>How to solve quadratic equations to get different answers</h3>

Quadratic equations of the form ax² + bx + c = 0 is solved using the formula

-b+\frac{\sqrt{b^{2}-4ac } }{2a}     OR     -b-\frac{\sqrt{b^{2}-4ac } }{2a}

The equation b² - 4ac is called the discriminant and it is used as follows

To solve the equation and get two real roots: 2x² - x + 3k = 0

  • b² - 4ac > 0

substituting the values gives

(-1)² - 4 * 2 * 3k > 0

1 - 24k > 0

1 > 24k

divide through by coefficient of k

k < 1/24

To solve the equation and get equal roots: 5x² - 2x + (2k − 1) = 0

  • b² - 4ac = 0

substituting the values gives

(-2)² - 4 * 5 * (2k - 1) = 0

4 - 40k + 20 = 0

-40k = -24

divide through by coefficient of k

k = 3/5

To solve the equation and get real roots  -x² + 3x + (k + 1) = 0

  • b² - 4ac > 0

substituting the values gives  

(3)² - 4 * -1 * (k+1) > 0

9 + 4k + 4> 0

4k > -13

divide through by coefficient of k

k > -3.25

To solve the equation and get  no real solutions  3kx² - 3x + 2 = 0

  • b² - 4ac < 0

substituting the values gives  

(-3)² - 4 * 3k * 2 < 0

9 - 24k² > 0

9 > 24k²

divide through by coefficient of k²

k² < 24/9

k < ± 1.633

Learn more about roots of quadratic equations: brainly.com/question/26926523

#SPJ1

4 0
9 months ago
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m_a_m_a [10]
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3 years ago
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{7TH GRADE} Create four (4) problems that include fractions. Solve the problems using estimation.
zaharov [31]

Answer:

Step-by-step explanation:

.

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2 years ago
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Geometry proofs<br> help me please :)
REY [17]

Answer:

2) Right angles always equal 90°

3) m∠F = 90° and m∠G = 90° which means they have the same angle measure.

4) Removing the m and replacing with the congruent symbol.

I'm not too sure how this goes but it should be something like that.

5 0
2 years ago
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