Answer: 7/2
To find the slope, we must put the equation in y = mx + b form, and m represents ur slope.
7x - 2y = 4....subtract 7x from both sides
-2y = -7x + 4 ...now divide both sides by -2
y = (-7/-2)x + (4/-2)
y = 7/2x - 2....now we have it in y = mx + b form, and since m is ur slope, ur slope in this equation is 7/2.
Answer:
the first function is correct
Answer:
The answer to this question would be B:
Based on the question, since the weight of the weight plates are 20 lbs, this would be represented by the 20x in the function. As well, the 5 lb barbell would be represented by the 5 in the function. The range of the function is determined by the amount of weight plates are added. So if I added one weight plate the equation would equal, f(x) = 20(1) + 5 = 25. This continues on the more and more weight plates you add.
Hope this reached you well :)
Step-by-step explanation:
20 = weight of the weight plates
x = amount of weight plates.
5 = weight of the barbell
f(x) = 20(0) + 5 = 5
f(x) = 20(1) + 5 = 25
f(x) = 20(2) + 5 = 45
f(x) = 20(3) + 5 = 65
f(x) = 20(4) + 5 = 85
Answer:
6,535.06 feet
Step-by-step explanation:
The set up is right angles
hypotenuse = 7000feet
angle of elevation = 21 degrees
Required
horizontal distance (adjacent)
Using SOH, CAH TOA trig identity
cos theta = adj/hyp
cos 21 = adj/7000
adj = 7000 cos 21
adj = 7000(0.9336)
adj = 6,535.06
Hence the HORIZONTAL distance until the plane flies over the island is 6,535.06 feet
