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asambeis [7]
3 years ago
10

Helppppp ASAPPPPPP TST FULL CREDIT

Mathematics
1 answer:
liraira [26]3 years ago
8 0

Answer:

24.

log_{2}(9)  \\  =  log_{2}(3)  {}^{2}  \\  = 3 log_{2}(3)  \\  =  \frac{3 log(3) }{ log(2) }  \\  = 4.75

25.

5. {9}^{x}  = 12.48 \\  {9}^{x}  = 2.496 \\ x log(9)  =  log(2.496)  \\ x =  \frac{ log(2.496) }{ log(9) }  \\ x = 0.42

26.

4 + 9. ln(x)  = 15.8 \\  ln(x)  =  \frac{15.8 - 4}{9}  \\  ln(x)  = 1.311 \\ x = e {}^{1.311}  \\ x = 3.71

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Adam is trying to solve the following riddle: "The sum of three consecutive integers is -36. What are the integers?" Solve Adam'
gladu [14]

Answer:

-13,-12,-11

Step-by-step explanation:

-13 + (-12) + -(11) = -36

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nata0808 [166]
<h3>Answer:  72%</h3>

Explanation:

The phrasing "given that he or she is a graduate" means we focus on the middle row only. We ignore everything else.

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OLga [1]

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4 0
3 years ago
a roller coaster train with 6 passenger cars and the front decoration has a mass of 3500 kg. when the train has the front decora
irinina [24]

Answer: The mass of each passenger is 550 kg.

The mass of front decoration = 200 Kg.

Step-by-step explanation:

Let the mass of each passenger be 'x'.

Let the mass of front decoration be 'y'.

So, Number of passenger = 6

Mass of 6 passengers and front decoration = 3500 kg.

Number of passengers = 4

Mass of 4 passengers and front decoration = 2400 kg.

According to question, it becomes,

6x+y=3500\\\\\implies y=3500-6x----------------(1)\\\\4x+y=2400\\\\\implies y=2400-4x---------------(2)

so, From Eq(1) and Eq(2), we have,

3500-6x=y=2400-4x\\\\3500-6x=2400-4x\\\\3500-2400=-4x+6x\\\\1100=2x\\\\x=\frac{1100}{2}=550

Hence, the mass of each passenger is 550 kg.

The mass of front decoration = 3500-550(6)=200 Kg.

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