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IgorLugansk [536]
3 years ago
10

I need how you found the answers?

Mathematics
1 answer:
lara31 [8.8K]3 years ago
8 0

Answer:

2x + 6 = -18

x + 1 = -11

3x = -36

Step-by-step explanation:

First find the solution! Then you can create your own equations

2x+9=-15

2x=-24

x=-12

Thus u need solutions with:

x = -12

Knowing the equation of a line as:

y = mx + b

we can can start by making y = -12 (our solution)

mx + b = -12

Now we can pick a value for m and b by adding and miltiplying on both sides

We do this to keep both sides equal.

if we make m = 2 and b = 3:

2x + mb = -12*m + 2b

2x + 6 = -24 + 6

2x + 6 = -18

Solving this we also get x = -12, as we expect.

An alternative way to think about it is to imagine that we start with a simple equation and make it more complex. We have our solution:

x = -12  => lets add a b value!

x + b = -12 + b => Lets add a slope (m)

xm + bm = -12m + bm

Giving values for this can give you multiple equation of the same solution.

General Formula:

m(x+b) = m(y+b)

mx + bm = my + bm

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Step-by-step explanation:

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2 years ago
To win a trivia game, Nathan must score at least 105 points. Each correct answer is worth \large 3\frac{1}{3} points, and each i
myrzilka [38]

Answer:

Nathan earned 100 points. he lost the trivia game by 5 points.

Step-by-step explanation

3\frac{1}{3} * 33 = 110 points earned

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3 0
3 years ago
A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco
sammy [17]

Answer:

No, we can't reject the dealer's claim with a significance level of 0.05.

Step-by-step explanation:

We are given that a local car dealer claims that 25% of all cars in San Francisco are blue.

You take a random sample of 600 cars in San Francisco and find that 141 are blue.

<u><em>Let p = proportion of all cars in San Francisco who are blue</em></u>

SO, Null Hypothesis, H_0 : p = 25%   {means that 25% of all cars in San Francisco are blue}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of all cars in San Francisco who are blue is different from 25%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 600 cars in San Francisco who are blue =   \frac{141}{600} = 0.235

            n = sample of cars = 600

So, <u><em>test statistics</em></u>  =  \frac{0.235-0.25}{{\sqrt{\frac{0.235(1-0.235)}{600} } } } }

                               =  -0.866

<em>Now at 0.05 significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that 25% of all cars in San Francisco are blue which means the dealer's claim was correct.

4 0
3 years ago
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