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IgorLugansk [536]
3 years ago
10

I need how you found the answers?

Mathematics
1 answer:
lara31 [8.8K]3 years ago
8 0

Answer:

2x + 6 = -18

x + 1 = -11

3x = -36

Step-by-step explanation:

First find the solution! Then you can create your own equations

2x+9=-15

2x=-24

x=-12

Thus u need solutions with:

x = -12

Knowing the equation of a line as:

y = mx + b

we can can start by making y = -12 (our solution)

mx + b = -12

Now we can pick a value for m and b by adding and miltiplying on both sides

We do this to keep both sides equal.

if we make m = 2 and b = 3:

2x + mb = -12*m + 2b

2x + 6 = -24 + 6

2x + 6 = -18

Solving this we also get x = -12, as we expect.

An alternative way to think about it is to imagine that we start with a simple equation and make it more complex. We have our solution:

x = -12  => lets add a b value!

x + b = -12 + b => Lets add a slope (m)

xm + bm = -12m + bm

Giving values for this can give you multiple equation of the same solution.

General Formula:

m(x+b) = m(y+b)

mx + bm = my + bm

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bixtya [17]

-8x⁵-12x⁴+30x³+19x²-4x-10

Step-by-step explanation:

-8x⁵+10x³+4x²-12x⁴+15x²+6x+20x³-10x-10..simplify

-8x⁵-12x⁴+10x³+20x³+4x²+15x²+6x-10x-10... like terms

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6 0
3 years ago
What is A divided by A% of A? <br> thank you!
Zina [86]
Suppose A equals 10. Lets use 20% of 10, or 2.

10/2 = 5.

As we can see, the equations varies depending on the percentage used. We can effectively conclude that:

A/(1/5A)
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Another example:

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4 0
3 years ago
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5 0
4 years ago
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A bag contains 3 red balls and 1 blue ball. A second bag contains 1 red ball and 1 blue ball. A ball is randomly picked from eac
Firlakuza [10]

Answer:

"2.82" seems to be the correct solution.

Step-by-step explanation:

As we know,

A bag (Bag A) contains,

Red balls = 3

Blue ball = 1

A second bag (Bag B) contains,

Red balls = 1

Blue ball = 1

Now,

⇒ P(Bag A, red ball) = P(A)\times P(r)\times P(r)

On substituting the values, we get

⇒                                = \frac{1}{2}\times \frac{3}{4}\times \frac{2}{3}

⇒                                = \frac{1}{4}

Similarly,

Probability of second bag will be:

⇒  P(Bag B) = \frac{1}{2}

hence,

In the first bag (Bag A), the expected number of red balls will be:

⇒  E(n)=\Sigma P(n)\times n

On substituting the values, we get

⇒           =3 (\frac{1}{4})+2(\frac{1}{8} )+4(\frac{1}{24} )+3(\frac{1}{12} )+3(\frac{4}{20} )+4(\frac{1}{20} )+2(\frac{3}{20} )+\frac{2}{20}

⇒           = \frac{169}{60}

⇒           =2.82

7 0
3 years ago
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Misha Larkins [42]

Answer:

thanks for the pts anyways

Step-by-step explanation:

6 0
3 years ago
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