Here is a motivational quote for your day:

Mathematics

2 answers:

Studentka2010 [4]3 years ago

6 0

Answer: AWWWWW Thank you That is some good motivational quote for me thank you it really made my day :) and also pls give me brainlest pls

Step-by-step explanation:

Alla [95]3 years ago

3 0

Answer:

thank you so much!

Step-by-step explanation:

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One solution to the problem below is 4. What is the other solution? y² - 16 = 0

ratelena [41]

Answer:

The 2 answers are 4 and -4

Step-by-step explanation:

8 0

3 years ago

Identify the degree and classify the polynomial by the number of terms. 3x+2

sasho [114]

Answer:

second degree

linear polynomial

Step-by-step explanation:

4 0

3 years ago

DUE TODAY!!!! I WILL MARK BRAINLIST

11Alexandr11 [23.1K]

Median: 3
mode: 3
range: 9
interquartile range: 2

the outliers are 9 and 5. there is a cluster between 2 and 3.

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3 years ago

About 33% of people who get their feet examined are found to have an ingrown toenail. What is the probability of a podiatrist ex

enot [183]

Answer:

The correct answer is 0.94147

Step-by-step explanation:

Let A denote the event that the podiatrist finds the first person with an ingrown toenail.

And (1 - A) denote the event that the podiatrist does not find the ingrown toenail.

While examining seven people, the podiatrist can find the very first person to have an ingrown toenail. Similarly he can find the second patient to have the ingrown toenail. Going in this way the probability of the first person to have an ingrown toenail is given by:

= A + (1 - A) × A + (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × A.

= $\frac{1}{3} + \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} .$

= $\frac{1}{3} + \frac{2}{3} \frac{1}{3} + (\frac{2}{3}) ^{2} \frac{1}{3} + (\frac{2}{3})^{3} \frac{1}{3} + (\frac{2}{3})^{4} \frac{1}{3} + (\frac{2}{3})^{5} \frac{1}{3} + (\frac{2}{3})^{6} \frac{1}{3}.$